For the function 𝑦𝑦 = −2𝑥𝑥2 + 4𝑥𝑥 + 1, what are the coordinates of the vertex? Is it a maximum or minimum point? Hint: use the vertex/axis of symmetry formula for 𝑥𝑥. Show all work algebraically to earn full credit and use Desmos only to check your answer.
y=2x^2+4x+1 **
One moment, I got it.
do you know this : if f(x) = ax^2 +bx +c so the vertex is (-b/2a , f(-b/2a) )
That is not right jhonyy
The vertex is (-1, -1)
It is a minimum value @Razor
\[f(x) = ax^2+bx + c \] ?
So here, let me write this all down: Vertex is at (-1, -1), and it is a minimum point.
That is standard form, what am I supposed to do with it?
Uhm, I'm supposed to have all the steps. Like how did you get to (-1,-1) ?
using my posted formula you get these value too
^
OOOOOOOOOH, ok
hahaha, I am used to doing math in my head
Srry about that
so do I just have to add the following equation I was given? Or graph it
Try graphing it first.
I will get the steps in a moment
@Razor you need learn this formula posted above
Yes, use johnyy's formula.
using this formula you can calcule the vertex of a quadratic
and how you decide that is minim or maxim ? just in this case bc. the vertex is (-1,-1) so give the value of 0 to x and so in this way for f(0) what value will get ?
I'm really not sure I'm sorry. Math is my nemesis
You can determine which is the maxim or minim based on the shape of the graph. For example: A graph in a "u" shape (like the one in this problem) The vertex is the point where it rounds at and changes direction. Since it is an up u, it would be a minimum, because of how low it is on the graph. Rather than if we had an "n" shape, where the vertex would be the highest, making it a maxim... Hope this helped!
Depends on the value of a if a >0 then minimum cuz opens up if a <0 then opens down or maximum
exactly @darkknight CONGRATS !!!
I am the darkknight
Yeah, that's my simplified explanation XD
@Razor , if you need your work shown: https://symbolab.com it will get all the work you need, because it is step by step calculator.
Yeah so if the line is positive it's a minimum, someone told me if it was negative it'd still be minimum
Unless it was a typo then it'd be maximum
Okay, I think I got it. abc. a = 2, b = 4 and c = 1
Which was super obvious but I didn't know if I was right or not until I look at it
so a is -2, which means that is opens down and it is a maximum
Does it determine if it's maximum or minimum by "a" and not the rest of the variables?
yes,
Hmm. I would look this up. I don't remember learning that.
\[x _{v} =-\frac{ 4 }{ 2*2} \]
Like that and then simplify
Yes, good job
Sweet, I think I got it from here. Thanks, guys. Sorry for dragging that out longer than it needed to be
No worries! I enjoy helping. And doing nerdy problems HAHAHA
XD
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