Question

a wire is carrying a 2.45 A current. at what distance from the wire is the magnetic field 1.00 x10^-6 T
?= m

Answer 1

\(\text{B} =\frac{\mu _{0}\text{I}}{2\pi \text{r}}\)

B is our magnetic field
\(\mu_{0} =4π10^{−7}~\frac{\text{T}\cdot \text{ m}}{\text{A}}\)
I is current
and r is the shortest distance to the wire

Answer 2

Plug and chug

Answer 3

can u plug it in for me

Answer 4

How difficult is it? What part of the plugging in confuses you?

Which variable are you confused about?

Answer 5

everything

Answer 6

nvm

Answer 7

What is the magnetic field that they gave you? It's in the question.

What is the current that they give?

Answer 8

I gave you the value of \(\mu_{0}\) a few posts about

And so once you put everything into the formula, you just have to multiply and divide and solve for 'r'

Answer 9

help me with this one
a 2.99 x 10^-6 C charge is moving perpendicular (90) to the earth magnetic field (5.00 x 10^-5 T). If the force on it is 2.14 x 10^-8 N, how far is it moving
? m/s

Answer 10

Let's make a new post for this

Answer 11

ok