Question

Find the area of the given figure.

Answer 1

a

Answer 2

what about 5 and 6?

Answer 3

first off, do you know the formula for area and perimiter?

Answer 4

ok. so the formula for area is A=L*W
Area = Length * Width

Answer 5

4 is 108 cm^2 correct?

Answer 6

let me see. i will work it out in my head

Answer 7

i got C for it. because i did the area of the retangle. then i did the area of the triangle and added those two together and got 139.5

Answer 8

i can't figure out the other two. i'm sorry

Answer 9

i don't remember that much. and also I got C for the 1st problem because it said to find the area, so that makes me thing the area of the whole shape

Answer 10

So if you know your area formulas, this would be a cinch. Let's do a bit of review. The area of squares and rectangles is as follows \[A = bh\] where A is area, b is the length of the base, and h is the height. It doesn't matter which is which in a rectangle or square, as they will both yield the same product. The area of a circle is as follows \[A = πr ^{2}\] where A is area and r is the radius squared. Finally, the area of a trapezoid is as follows \[A = h(\frac{ b1+b2 }{ 2})\] where b1 is the length of one base, b2 is the length of the other parallel base, and h is the height of a trapezoid. Now we have all the tools that are necessary to finish this problem,

Answer 11

So let's start with the second problem. For this one, you're given a 5 sided figure. However, because we don't currently know the area formula for this shape, we can simply divide it into TWO different shapes. So you can divide that figure into a rectangle and a trapezoid.
Sorry for the bad drawing, but this is the sketch of what I am talking about. Just use those area formulas to figure out the area of both of these shapes, and simply combine the areas of both together.

Now for the third problem, we have a circle inscribed inside of a square, and I'm assuming you are looking for the area inside the square, but outside of the circle. Well, we know what the area of the square is. Now to find the area of the circle. You just simply find the radius, which is half the diameter of the circle. This is also known to be half of the length of the square. This is what the operation would look like. \[(10/2)^{2}\] Now just plug that into the area formula. Now, the trick to finding the area outside of the circle, but inside of the square is subtracting the area of the circle from the square, as the square has more area than the circle and the circle is also inscribed in the square. So it would essentially be \[A = bh - πr ^{2}\] I hope this helps.

Answer 12

For 4, you have to add the areas of both the rectangle and the triangle. For the area of the triangle, the formula is as follows\[A = \frac{ bh }{ 2 }\] where b is the base of the triangle and h is the height of the triangle. As I have stated before, you must use the area formula for the rectangle/square to find that area. Then just find the area of the triangle with the formula given above. Add those two values and you'll find the area of the pentagon.

Answer 13

I am not allowed to give an actual answer, but I am allowed to guide you. Remember, the area you are looking for is a PENTAGON. NOT JUST a rectangle. Remember, the pentagon is composed of a rectangle and a triangle. So how do you find the area of the pentagon, while taking into account both the areas of the rectangle and the triangle?

Answer 14

The formula for a rectangle is simply A = bh. As long as you plug in the right side lengths and multiply them together, then you will find the area. If you have completed that process, then there is nothing to worry about regarding the area of the rectangle.

Answer 15

Please reread the messages I sent above.

Answer 16

\(\color{#0cbb34}{\text{Originally Posted by}}\) @InsatiableSuffering
For 4, you have to add the areas of both the rectangle and the triangle. For the area of the triangle, the formula is as follows\[A = \frac{ bh }{ 2 }\] where b is the base of the triangle and h is the height of the triangle. As I have stated before, you must use the area formula for the rectangle/square to find that area. Then just find the area of the triangle with the formula given above. Add those two values and you'll find the area of the pentagon.
\(\color{#0cbb34}{\text{End of Quote}}\)
Reread this in particular.

Answer 17

\(\color{#0cbb34}{\text{Originally Posted by}}\) @InsatiableSuffering
So if you know your area formulas, this would be a cinch. Let's do a bit of review. The area of squares and rectangles is as follows \[A = bh\] where A is area, b is the length of the base, and h is the height. It doesn't matter which is which in a rectangle or square, as they will both yield the same product.
\(\color{#0cbb34}{\text{End of Quote}}\)
Hopefully, this part answers your latest question