Question

Jeff has 5 red pens and 1 blue pen in his backpack. He also has 4 yellow highlighters and 1 green highlighter in his backpack. If he reaches into his backpack and grabs one pen and one highlighter without looking, what is the probability that he will grab a red pen and a green highlighter? can sum 1 help plz

Answer 1

This isnt 4/3

Answer 2

Oh god, @dude pls

Answer 3

Id explain this but Im doing something, please wait a moment KingSquid c:

Answer 4

oh my gosh thank u so much ive been stuck on this for a while

Answer 5

So in order to calculate the probability of pulling out a green highlighter and a red pen, we have to take into account the total number of pens and highlighters together. We have a total of 6 pens and 5 highlighters. Now let's find out how many of them are red pens or highlighters. We know that we have 5 red pens and 1 green highlighter. So the probability for grabbing a red pen is 5/6, while grabbing a green highlighter is 1/5. Because these are two separate events that occur and it asks for both a green highlighter and the red pen to be pulled out in quick succession, you would multiply those probabilities together, yielding a percentage of both events occurring at the same time.
\[\frac{ 5 }{ 6 }*\frac{ 1 }{ 5 }\]

Answer 6

so it would be 1/6 ?

Answer 7

Indeed it would be.

Answer 8

alrighty thank u