2) In a closed system, Glider A with a mass of 0.50 kg and a speed of 1.50 m/s collides with Glider B at rest with a mass of 0.30 kg. The two interlock and move off. What speed are they moving?
1.3125 = 1.31 m/sec

Question

jennylove · Answer

i think its 1.31 ^

ramen · Answer

i think so?

ramen · Answer

idk yet

kittybasil · Answer

Closed system = conservation of momentum. Equation:$$\Large{m_1u_1+m_2u_2=m_1v_1+m_2v_2}$$When the body is at rest, $u_2=0$. Also, $v_1=v_2=v$ since both interlock and move together. As a result, your equation is now$$\large{m_1u_1+m_2(0)=m_1v+m_2v}$$$$m_1u_1+0=m_1v+m_2v$$We know that your values are as follows:$$m_1=0.50\text{kg, }m_2=0.30\text{ kg, }u_1=1.50\text{ m/s}$$

kittybasil · Answer

Plugging in those values, we get$$(0.50\text{ kg})(1.50\text{ m/s})+0=(0.50\text{ kg})v+(0.30\text{ kg})v$$Simplifying, we now have$$0.50(1.50)=0.50v+0.30v$$We can reverse distribute (source: Distributive Property) the right side to isolate the variable $v$:$$0.50\cdot1.50=v(0.50+0.30)$$Simplifying again,$$0.75=v(0.80)$$As a result, your variable should be the result of this.$$0.75\div0.80=v$$

kittybasil · Answer

Edit: sorry, velocity variable $v$ should be your "speed" that the question is asked for.
If you solve that expression it should give you the answer

kittybasil · Answer

@jennylove Everything alright?
If you have any questions, feel free to ask for further assistance :)

jennylove · Answer

@kittybasil  wow thank you for this deep explanation ! I found the answer to be 0.9375 m/s by using the info you gave me , am i correct?

kittybasil · Answer

Yeah, that should be correct.
But if you need to round up or down, don't forget to do that! :)

jennylove · Answer

Okay, thank you so much! youve been very helpful