Question

only question #5 questions plz help

Answer 1

for 4 take the derivative of the function, set it equal to 0, and solve for x. that x value is the # of refridgerators at the maximum profit. plug that x-value back into the original function to find the profit

5a. if f(x) is your function and F(x) is the antiderivative...



applying this to 5a, take the integral, then evaluate F(4) - F(1)

same logic with 5b

Answer 2

can you show me exactly the steps to do 5a? thanks @Vocaloid

Answer 3

integral of 6x is 3x^2
integral of 3/x is 3ln(x) (if you don't understand these, review your derivative and integration rules)

so your antiderivative is F(x) = 3x^2 - 3ln(x)

then evaluate F(4) - F(1) as these are the limits of integration

Answer 4

okay I got his part, what do you mean evaluate 1,4 do I pplug them in??

Answer 5

yes

Answer 6

3(4)^2 - 4 ln 4 = 53
3(1)^2 - 1 ln 1 = 3
53 - 3 = 50??
right? @Vocaloid

Answer 7

you don't change the 3 in front of the ln(x)

3x^2 - 3ln(x) ---> [3(4)^2 - 3ln(4)] - [3(1)^2 - 3ln(1)]

Answer 8

the answer is now equal to 49

Answer 9

but if you plug the whole thing in the calculator the answers need to be 40.8 @Vocaloid

Answer 10

you made a mistake in your arithmetic somewhere. check again.

Answer 11

so it should not be 49? im also using the calulator

Answer 12

if you're having trouble just use an online calculator
wolframalpha.com
and plug in this [3(4)^2 - 3ln(4)] - [3(1)^2 - 3ln(1)]

Answer 13

Sorry I gotta bail for a bit

@imqwerty would you mind helping? we just need to wrap up 5a and start 5b, it's just a basic u-sub problem

Answer 14

thank you!

Answer 15

@May567 did you remove the question? I can't find it