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leila123456:

What is the speed of a wave with a frequency of 2 Hz and a wavelength of 87 m? 0.023 m/s 43.5 m/s 89 m/s 174 m/s

leila123456:

I keep getting the wroung the answer

QuestionCoveBot:

What do you keep getting?

leila123456:

A negative

QuestionCoveBot:

The speed of a wave is given by where is the wavelength of the wave is the frequency of this problem, we have a wave of wavelength and frequency.

QuestionCoveBot:

Sorry if it's hard to read, I messed all the time.

leila123456:

It's fine

leila123456:

So we find for the speed?

QuestionCoveBot:

The first one and the second one can go because there the slowest, and the human eye would be able to see them. - The second one would have to be seen with a telescope, to your eye. - Do you get what I mean?

leila123456:

yes

leila123456:

ok

QuestionCoveBot:

89 m/s wouldn't be seen by?

leila123456:

the human eye

QuestionCoveBot:

and

QuestionCoveBot:

small tele's

leila123456:

A telescope

QuestionCoveBot:

*Small telescope*

leila123456:

oh

QuestionCoveBot:

So, what do you get?

QuestionCoveBot:

174 m/s? or 89 m/2?

leila123456:

Um.....is it 174 m/s

QuestionCoveBot:

Good job. :)

leila123456:

Thank you :3

QuestionCoveBot:

@QuestionCoveBot

leila123456:

k

justjm:

@QuestionCoveBot is correct here but you can't reason through the question by seeing if it's visible to the naked eye or you're likely to get other questions wrong...you're gonna have to do the math here. \[v=\lambda f\] Here you are given \(\lambda=87~m,~~f=2~Hz\) So you can plug that in Remember that \(1~Hz=1~s^{-1}\), so your final unit would still be m/s as indicated in the answer choices. Plugging that in... \[v=(87~m)(2~s^{-1})\] \[=174~m/s\]

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