A supervisor has determined that the average salary of the employees in his department $40,000 with a standard deviation of $15,000. Assume that the distribution of the salaries is normally distributed. An employee is selected at random, find the probability that the employee’s salary is:

(i) More than $35,000.
(ii) Between $36,000 to $42,000.

Question

A supervisor has determined that the average salary of the employees in his department  $40,000 with a standard deviation of $15,000. Assume that the distribution of the salaries is normally distributed. An employee is selected at random, find the probability that the employee’s salary is: 
 
(i) More than $35,000. 
(ii) Between $36,000 to $42,000.

blastzone11 · Answer

Add it up

atuwaqa · Answer

I'm abid confuse with your ans?

atuwaqa · Answer

wrong

atuwaqa · Answer

question is ?,what is the probability of getting a salary of more than $35000

blastzone11 · Answer

Is there

Mercury · Answer

remember the z-score formula

z = (value - mean)/(standard deviation)

converting the z-score to a probability (via calculator or z-table) will give you the probability of getting a value below the specified "value"

I'll demonstrate with the first problem

i) "more than 35,000" ---> let 35,000 be the value, mean is 40,000, standard deviation is 15,000. calculate the z-score, and convert this to a probability. now, since this gives you the probability of getting a value less than 35,000, take 1 - (the probability) to get the opposite situation (getting a value more than 35,000)

Mercury · Answer

ii) between 36,000 and 42,000

if we subtract P(getting less than 42,000) - P(getting less than 36,000) you will get the probability in between the two values. (sketch this yourself to confirm)

calculate the z-scores for 36,000 and 42,000, convert to the probabilities, then subtract