Question

Why is oxygen the limiting reactant in this equation? https://drive.google.com/file/d/1wl5LCAgAUOtsuZj3INiHhByLTHXRwBas/view?usp=sharing

Answer 1

notice how the O2 produces fewer moles of CO2

therefore, if you had both 35.0 moles of C2H2 and 84.0 moles of O2 in the reaction flask, the O2 would run out first and the yield would be 67.2 mol CO2. Once the O2 runs out, there would be C2H2 by itself, along with the product, but without more O2 to react with, the reaction stops.

Hope that makes more sense, lmk if you're still confused