Question

Part A: If (62)x = 1, what is the value of x? Explain your answer.
Part B: If (60)x = 1, what are the possible values of x? Explain your answer. HELP ASAP

Answer 1

(6^2
)x = 1

Answer 2

it should be exponents

Answer 3

this one is better

Answer 4

Ah that helps, thank you

Answer 5

Yw

Answer 6

jorellcross press the screenshot its better

Answer 7

what is annswer for part A and part B

Answer 8

What you need to remember is that anything to the 0 power will give you 1
Remember the power rules.
\(\large (a^x)^y=a^{x\times y}\)


So, you want to get the exponents to get to 0 (For the first part)
Since there is a zero in the second exponent, any x value will work

Answer 9

how do you do that

Answer 10

2 times what will give you 0?

Answer 11

0

Answer 12

The rule is that anything multiplied by 0 is equal to 0

Answer 13

Yeah

Thats your answer for A

Answer 14

but a doesent have 0

Answer 15

Oh ig that makes sense

Answer 16

What do I say for part A?

Answer 17

You can say something along the lines of the possible value of x would be 0 because "The rule is that anything multiplied by 0 is equal to 0"

However please do not copy-paste word-for-word what I write

Answer 18

Yessir i use from my words

Answer 19

What do I say for part B?

Answer 20

U workin on it

Answer 21

Oh I goofed for A

Same idea follows, just steps are different

\((6^2)^x\)

My mistake **Solve \(6^2\) first then find x**

This should be \((36)^x\)

To get 1, you can now multiply by 0

\(x=0\)

Answer 22

thats for b or a

Answer 23

Now for B, since the exponent is already 0

You have,

\(6^0=1\)

Now you get
\((1)^x\)

From then you should know what x should be

Answer 24

x is 0 right

Answer 25

x=0 for part A, yes

Answer 26

for part B?

Answer 27

\(1^x=1\)

Do you know how to solve this?

Answer 28

yes

Answer 29

1x1

Answer 30

what are the possible values of x

Answer 31

Hmm yes that is true but,


\(1^1=?\)
\(1^2=?\)
\(1^3=?\)
\(1^4=?\)

Answer 32

its only 1

Answer 33

Yeah

Answer 34

They all work

Answer 35

Okay so what do i say for possibilities

Answer 36

11=?
12=?
13=?
14=?

Answer 37

No, I wrote that for you

Answer 38

ik

Answer 39

Since the exponent is already 0 You have, 6^0=1 Now you get 1. The possibilities are 1^1, 1^2, 1^3, 1^4.

Answer 40

I wrote this

Answer 41

is this good or bad

Answer 42

You get 1^x, not just 1

Answer 43

x can be any whole number, not just 1,2,3,4

Answer 44

Yo thx for reminding me i was like ill fix that later

Answer 45

ty