Question

Julie is filling up her water jug before soccer practice.
The jug already contained 20 fluid oz of water and is being filled at 3 fluid oz per minute.
Brian was also filling his water jug but it contained 34 fluid oz of water and was being filled at a rate of
2 fluid oz per minute.
What equation can be written to show, x, the number of minutes that need to pass, before both jugs
have the same amount of water in them? (write the equation and solve)

Answer 1

So, we will end up having two equations, one for Julie and one for Brian

Both are being filled at a constant rate, so we can use the linear equation

\(y=mx+b\)
m is the rate
b is the starting amount


With this in mind, do you have an idea on what to do?

Answer 2

idk

Answer 3

\(y=mx+b\)
m is the rate
b is the starting amount


For Angie, what is the rate at which the jug is being filled?
What is the starting amount?

Answer 4

20?

Answer 5

She starts at 20 yes

Her rate is?

Answer 6

3

Answer 7

Yeah, so we can just substitute that into the equation

\(y=3x+20\)

Do you know how I got there?

Answer 8

yea

Answer 9

so know we just gotta solve tha righ

Answer 10

We also have to make the equation for Brian

Do you now know how to?

Answer 11

nah

Answer 12

`Brian was also filling his water jug but it contained 34 fluid oz of water and was being filled at a rate of 2 fluid oz per minute.`

What is the starting amount?
What is the rate?

Answer 13

34 and 2

Answer 14

Right, so you can make the second equation now

\(y=2x+34\)

Answer 15

Now, you want to find when they are **equal**

How would you know if two equations are equal?

Answer 16

ight

Answer 17

by solvin them?

Answer 18

Sure, do you know how you'd solve them?

Answer 19

yea

Answer 20

wait so it x=14 right

Answer 21

Yeah

Answer 22

ight thxs