Question

Given the function h(x)=x^2-7x+8h(x)=x
2
−7x+8, determine the average rate of change of the function over the interval 2≤x≤10.

Answer 1

h(x)=x^2-7x+8h(x)=x

Answer 2

\(h(x)=x^2-7x+8\)

Bet just substitute 2 and 10 like b4

Answer 3

2^2-7(2)+8?

Answer 4

Yes (:

Answer 5

10^2-7(10)+8?

Answer 6

Yes againe :)

Answer 7

Tearing up rn

Answer 8

I finally get math

Answer 9

Same bro, im proud :')

Answer 10

:')

Answer 11

-2 and 38

Answer 12

-19 ?

Answer 13

So close on the process :(

\(\dfrac{38--2}{10-2}\)

Answer 14

5 o-o

Answer 15

Si

Answer 16

Almost got it

Answer 17

Yes :)

Answer 18

h(x)-x^2-9x+26

-6 ≤ x ≤ -1

Answer 19

Would that make 6 positive

Answer 20

Are you asking about the domain?

-6 <= x <= -1?


That looks fine

Or are you asking for answer check

Answer 21

When plugging it in

Answer 22

The first one would remain negative, the second will be positive

\(-(-6)^2-9(-6)+26\)

\(-36+54+26\)

Answer 23

\(-(-1)^2-9(-1)+26\)


\(-(-1)^2=-1\)
\(-9(-1)=9\)

\(-1+9+26\)

Answer 24

34 and 44

Answer 25

Yes

\(\dfrac{34-44}{-1--6}\)

Answer 26

-2

Answer 27

Yes

Answer 28

x^2+10x+21

-10 ≤ x ≤ -3

Answer 29

-10^2+10(-10)+21
3^2+10(3)+21

Answer 30

\((-3)^2+10(-3)+21\)

Answer 31

Yes negative

Answer 32

Yes good (:

Answer 33

-179 and -18

Answer 34

So
-179-(-18)/-10-(-3)

Answer 35

Hmm I didn't get -179 and -18

Answer 36

Bruh

Answer 37

\((-3)^{2}+10(-3)+21\)

\(9-30+21\)

\(-21+21\)

Answer 38

\(-10^2+10(-10)+21\)

\(100-100+21\)

Answer 39

0 and 21

Answer 40

Yeah

Answer 41

Okay

Answer 42

\(\dfrac{0-21}{-3--10}\)

Answer 43

Then what

Answer 44

-3

Answer 45

Yes