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Mathematics 9 Online
MiraAngel:

An infinite geometric series has a first term a1=15 and a sum of 45. Explain how you can use the formula S=a1/(1-r) to find the value of the common ratio. What is the value of r? Attach a screenshot of your work

glizxzy:

@dude i dont know

MiraAngel:

lol kk Thx!

glizxzy:

can you help her

glizxzy:

dude

glizxzy:

@Ultrilliam can you help her

dude:

Oh this is straightforward They already give you the formula to find the rate \(\sum=\dfrac{a_1}{(1-r)}\) \(\sum \) is just sum You know the sum and the \(a_1\) value, just substitute them both in and isolate r Do you know how to do that or are you confused?

MiraAngel:

confused cause as soon as I put those into the equation I can't figure out how to get r by itself.

dude:

What equation do you have right now?

MiraAngel:

S=a1/(1-r) 45=15/(1-r)

dude:

Yeah looks good \(45=\dfrac{15}{(1-r)}\) Because of the awkward nature of the denominator, we just want to multiply the whole factor by the denominator \(\color{green}{(1-r)~\times } ~45=\dfrac{15}{\color{red}{\cancel{(1-r)}}}\color{red}{\cancel{{\times (1-r)}}}\)

MiraAngel:

Oh! okay! Thank you!

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