Question

Solve x2 + 6x + 7 = 0.

x = −1 and x = −5
3 plus or minus square root of 2
negative 3 plus or minus square root of 2
quantity of negative 3 plus or minus square root of 2 all over 2

Answer 1

In the place of x put -1 and show me what you get

Answer 2

i got -1 i think

Answer 3

Watch this

Answer 4

(-1)2 + 6(-1) + 7 = 0.
-2 -6 + 7 = 0
-8 + 7 = 0
? = 0

(-5)2 + 6(-5) + 7 = 0
-10 -30 + 7 = 0
-40 + 7 = 0
?=0

Answer 5

Solve that and tell me if the question mark is equal to 0

Answer 6

its nottt

Answer 7

Good
What is the square root of 2?

Answer 8

1. somethin
im dumb im sorry

Answer 9

It's 4

Answer 10

sorryyy math aint my strong suit

Answer 11

BRUHH ITS FINE

Answer 12

It's fine
(3+ 4)2 + 6(3 + 4) + 7 = 0.
(7)2 + 6(7) + 7 = 0
14 + 32 = 0
? = 0

(3-4)2 + 6(3-4) + 7 = 0
-2 -6 + 7 = 0
-8 + 7 = 0
?=0

Answer 13

Are they the same...the question marks....and do they equal 0?

Answer 14

nopee

Answer 15

Good

Answer 16

So that leaves us with our obvious answer

Answer 17

OH WHOOPS I am really sorry about that we have one more! LOL

Answer 18

awhh aha youre good! i was sittin there like well see sir its not too obvious to me quite yet lol

Answer 19

(-3+ 4)2 + 6(-3 + 4) + 7 = 0.
(1)2 + 6(1) + 7 = 0
2 + 6 = 0
? = 0

(-3-4)2 + 6(-3-4) + 7 = 0
(-7)2 -6(-7) + 7 = 0
-14 - 32 + 7 = 0
?=0

Answer 20

yeah that isnt it either

Answer 21

so quantity of negative 3 plus or minus square root of 2 all over 2

Answer 22

Correct good Job!

Answer 23

thank you so much man i really appreciate your help

Answer 24

Quick check:

1. The equation likely is \( x^2 + 6x + 7 = 0\), where the first x is squared.
2. The square root of 2 is *not* 4. It's irrational.
3. A quick solution to this is to use the quadratic equation (shown below)

\(\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\)


Where each value is defined by \(a^2+bx+c\) in the original equation