Ask your own question, for FREE!
Mathematics 4 Online
ura23ramo:

Devin is collecting signatures for a petition to open a new park in her town. She needs to collect at least 1,000 signatures before she can schedule a meeting with the mayor. She already has 380 signatures. If each petition page holds 80 signatures, which inequality best shows how many more pages (p) Devin needs?

supie:

Ok so \(p\) represents \(\bf pages\) "She needs to collect at least 1,000 signatures" it says \(\bf at~ least\) meaning that it has to be ≥ so she has to have any number greater than or equal to 1,000 (amount of signatures)

supie:

So it says she already has 380 signatures so that means 1,000 – 380 would be how much she still needs left but what we're trying to find is `what inequality best shows how many more pages` So you didn't provide the answer choices - which is ok

supie:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @supie Ok so \(p\) represents \(\bf pages\) "She needs to collect at least 1,000 signatures" it says \(\bf at~ least\) meaning that it has to be ≥ so she has to have any number greater than or equal to 1,000 (amount of signatures) \(\color{#0cbb34}{\text{End of Quote}}\) So back to this we're trying to find what inequality best shows how many more pages like I said before '"She needs to collect at least 1,000 signatures" it says \(\bf at~ least\) meaning that it has to be ≥ '" So you have to subtract 380 from 1,000 to get how much more she needs (Keep in mind that it says each page holds 80 signatures Meaning that 80 signatures/page or 80 signatures per page (80:1) So when we subtract 380 from 1,000 we get 620 Meaning that we have to do 620÷8 (\(\frac{620}{8}=\sf~amount~of~pages~needed)\) If you solve that, then you'll have the amount of pages needde

supie:

needed*

supie:

So then from there you can find the inequality

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!