Determine the number and type of solutions to the equation x^2+7x=−11.
^that has nth to do with my question, but ok
nice im trying lol
@jhonyy9
x^2 +7x +11 = 0 this is your quadratic ?
yes
did you heard about discriminant ?
yes
and about the roots of quadratic in function of discriminant > 0 or = 0 or < 0 ?
yeah,i think so
ok when the discriminant D > 0 how are the roots of quadratic ?
so if ur asking what i think you are, then she told us if the discriminant is =0, there is one real solution, and if D>0 , then there is 2 real solutions and then if D<0, there are no real (2 imaginary) solutions
exactly perfect
so then we do \[b^2-4ac\] which is then going to be \[7^2-4(1)(11)\]
so sorry a quadratic has always two roots so in case when D=0 than x_1 = x_2
ok ?
\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9 so sorry a quadratic has always two roots so in case when D=0 than x_1 = x_2 \(\color{#0cbb34}{\text{End of Quote}}\) im confused about this
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Timothykisel \(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9 ok ? \(\color{#0cbb34}{\text{End of Quote}}\) How do you guys know these stuff \(\color{#0cbb34}{\text{End of Quote}}\) im learning in in algebra class?
\(\color{#0cbb34}{\text{Originally Posted by}}\) @mxddi3 \(\color{#0cbb34}{\text{Originally Posted by}}\) @Timothykisel \(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9 ok ? \(\color{#0cbb34}{\text{End of Quote}}\) How do you guys know these stuff \(\color{#0cbb34}{\text{End of Quote}}\) im learning in in algebra class? \(\color{#0cbb34}{\text{End of Quote}}\) ah
yes so D = ?
i got 5 when i solved it
so D = 5 > 0 result what ?
2 solutions to the quadratic. but idk if there's anything else i have to do after this
2 real solutions that 's all i think
ok, ty!
yw anytime is my pleasure bye bye
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