Question

Math questions! please help if you can! Thanks!

Answer 1

like a first step so do you know the equation of a hyperbola ?

Answer 2

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9
like a first step so do you know the equation of a hyperbola ?
\(\color{#0cbb34}{\text{End of Quote}}\)
Yes. It's either
Vertical: y^2/a^2 - x^2/b^2 = 1
or
Horizontal: x^2/z^2 - y^2/b^2 = 1

Answer 3

since the co-vertices are present on the y-axis, it's a horizontal hyperbola

Answer 4

Okay! Thank you... so I would use this equation.... x^2/a^2 - y^2/b^2 = 1

Answer 5

why not this-

\(\Large{\frac{(x-h)^2}{a^2} - \frac{(y-k)^2}{b^2} = 1}\)

where (h, k) is the center of the hyperbola

Answer 6

is the center at (0, 0)?

Answer 7

yup

Answer 8

okay! How would I find a and b?

Answer 9

\(\color{#0cbb34}{\text{Originally Posted by}}\) @MiraAngel
is the center at (0, 0)?
\(\color{#0cbb34}{\text{End of Quote}}\)
But do you know how?

Answer 10

cause the co-vertices are the same distance from (0, 0)?

Answer 11

not exactly. check this case- https://www.desmos.com/calculator/kijvqflnjo
the center doesn't even lie on the line joining the co-vertices but is at the same distance from the co-vertices

Answer 12

ohhhhhhh ok

Answer 13

how to find the center-
it's the middle point of the line joining the co-vertices. So it's at the same distance from the co-vertices + it lies on the line joining the co-vertices

Answer 14

ok! What would a and b be? How would I find those?

Answer 15

use this

Answer 16

Use the images and the given info in the question. that's enough info to find a and b

Answer 17

okat. Thank you!

Answer 18

*okay