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Mathematics 14 Online
kayla233:

Choose ONE of the following sequences and write​ the arithmetic or geometric EXPLICIT formula. Then use ​ your explicit formula to find the 18th term. (show all work)​ ​ A) 3, 7, 11, 15,…...​ B) 2, 6, 18, 54,…...​ C) 6, 2, -2, -6,…...​

darkknight:

@darkknight 5 min l8r

kayla233:

?

darkknight:

ill get to u in 5 min.

kayla233:

oh, I need it right away my teacher needs the notes in 10 minutes and I still have a lot but it's okay :)

kayla233:

yea

darkknight:

nvm, i see it

kayla233:

ok

darkknight:

So which one do you want to choose? A B or C?

kayla233:

I think it b but I suck at math so idk

darkknight:

alright, lets work on B, So we can see that B) 2, 6, 18, 54,…...​ the numbers are multiplied by 3 every time, starting at 2. So what do you think the arithmetic or geometric explicit formula will look like?

kayla233:

im not sure. I haven't worked a lot on arithmetic and geometric formulas

darkknight:

okay lets use the formula \[a _{n} = a _{1} + (n-1)d\] this familiar to you?

kayla233:

not really but we can use it

darkknight:

It is basically saying that a n is equal to the 1st term + common difference (n-1)

kayla233:

okay

darkknight:

oops I got the wrong one. :( So what i mean is that \[a _{n}= (a _{1}) (r)^(n-1)\] Where r is the common ratio, in this case 3, a1 is initial value of in this case 2. So we have an = 2 times 3^(n-1)

darkknight:

Sorry this is very messy, so basically \[a _{n} = 2(3)^(n-1)\] N-1 is in the exponent btw

kayla233:

Okay thank you for your help so far

darkknight:

Now thats the formula, so plug in 18 for n and see what you get

darkknight:

No problem, If you want to drop a medal (best response) and have a good day :)

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