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Chemistry 13 Online
cheyenneminus:

How many moles of oxygen are needed to burn 1.33 moles of methyl alcohol (CH3OH)? 2CH3OH + 3O2 2CO2 + 4H2O

justus:

As we see from the balanced reaction: 2CH3OH + 3O2 2CO2 + 4H2O We come to the conclusion that 3 moles of oxygen, 2 moles of methyl alcohol react together.  Therefore, 1,33 moles of methyl alcohol react with 3/2 * 1.33= After calculating this number you will have the number of moles of oxygen that are needed to be burned. Hope this helps.

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