Question

Given the function h(x) = 3(5)x, Section A is from x = 0 to x = 1 and Section B is from x = 2 to x = 3.

Part A: Find the average rate of change of each section. (4 points)

Part B: How many times greater is the average rate of change of Section B than Section A? Explain why one rate of change is greater than the other. (6 points)

if you help me with this ill give you modded cars on gta ps4 :)

Answer 1

Is that x an exponent?

Answer 2

one sec

Answer 3

which x ?

Answer 4

h(x) ?

Answer 5

when you wrote 3(5)x

Answer 6

i dont think so

Answer 7

I'm curious if it says \[3(5)^x \] the x being higher than the 5 and smaller in font size too

Answer 8

its not like that on the question its above it if thats what you mean

Answer 9

If you can please post a screenshot of the full problem

Answer 10

ok lemme find out how to screen shot rq im on school computer

Answer 11

Thanks that clears up everything

Answer 12

your welcome dad

Answer 13

sir*

Answer 14

So what we need to do first is plug in x = 1 into h(x)
What do you get when you do that?

Answer 15

how would you plug it in ?

Answer 16

dont give answer just explain how to

Answer 17

you replace every x with 1
Then use PEMDAS or your calculator to evaluate
h(x) = 3(5)^x
h(1) = 3(5)^1
h(1) = ??

Answer 18

one second please

Answer 19

sure thing

Answer 20

im getting help on this lmao

Answer 21

45?

Answer 22

what is 5^1 equal to

Answer 23

5^1 means 5 to the power of 1
We can write that as \(5^1\)

Answer 24

the answer is 45

Answer 25

I'm not sure how you're getting 45. Is your calculator saying \[5^1 = 45\] or something else?

Answer 26

wdyem

Answer 27

wdyem= what do you even mean

Answer 28

i got the answer but i just need to know if its right

Answer 29

you there????

Answer 30

did you leave to get the milk again???? :(