Question

An airplane taking off from a landing field has a run of 500m. If it starts from rest, moves with constant acceleration, and makes the runin 30s, with what velocity in m.s-¹ did it tak e off ?

Answer 1

Is there choices?

Answer 2

Do you know if theres a formula for this?

Answer 3

If you find the formula that needs to be used, then you could plug in the numbers and solve the equation.

Answer 4

SUVAT

u = 0
s = 500
t = 30
a = constant, ergo SUVAT
v <-- what you want to know

\(s = ut + \dfrac{1}{2} a t^2 \implies 500 = \dfrac{1}{2} a (30)^2\)

\(\therefore a = \dfrac{2 \times 500}{30^3}= \dfrac{10}{9} m s^{-2}\)

\(v = u + at = \dfrac{10}{9} \times 30 = 30~m/s\)

#Utopia