An airplane taking off from a landing field has a run of 500m. If it starts from rest, moves with constant acceleration, and makes the runin 30s, with what velocity in m.s-¹ did it tak e off ?

Question

supie · Answer

Is there choices?

supie · Answer

Do you know if theres a formula for  this?

supie · Answer

If you find the formula that needs to be used, then you could plug in the numbers and solve the equation.

SemiDefinite · Answer

SUVAT

u = 0
s = 500
t = 30
a = constant, ergo SUVAT
v <-- what you want to know

$s = ut + \dfrac{1}{2} a t^2 \implies  500 = \dfrac{1}{2} a (30)^2$

$\therefore a = \dfrac{2 \times 500}{30^3}= \dfrac{10}{9} m s^{-2}$

$v = u + at = \dfrac{10}{9} \times 30 = 30~m/s$

#Utopia