Question

Can I get some help on conic sections?

Answer 1

@hero or @darkknight

Answer 2

jesus-

Answer 3

uh

Answer 4

xio

Answer 5

Yeah?

Answer 6

ill try-

Answer 7

\(\color{#0cbb34}{\text{Originally Posted by}}\) @IamAku
ill try-
\(\color{#0cbb34}{\text{End of Quote}}\)
Lol okayy

Answer 8

wait-

Answer 9

how'd u get ur first answer-

Answer 10

I clicked on it accidentally and I can't unclick it >.>

Answer 11

oh

Answer 12

Hmm not quite

The center point in the equation will be the opposite of the sign in the graph itself

(x-1)^2+(y-2)^2 will give you point (1,2)


Then, the right side is the radius squared (:

Answer 13

thx dude

Answer 14

my brain is kinda-

Answer 15

yh-

Answer 16

\(\color{#0cbb34}{\text{Originally Posted by}}\) @dude
Hmm not quite

The center point in the equation will be the opposite of the sign in the graph itself

(x-1)^2+(y-2)^2 will give you point (1,2)


Then, the right side is the radius squared (:
\(\color{#0cbb34}{\text{End of Quote}}\)
Ohh, it's still kind of confusing though..

Answer 17

What's the center point in the graph?

Answer 18

(-1,-2)

Answer 19

ok and what are the other 4 points that make it a circle

Answer 20

Yeah

For the x and y in the parenthesis you want it to have the opposite sign

\((x\color{red}{+}1)^2+(y\color{red}{+}2)^2\) -> (-1,-2)

For the right side of the equation
You had =7

The radius is 7 but the equation is \(r^2\)

So, just square 7

Answer 21

so what would be your awnser

Answer 22

\(\color{#0cbb34}{\text{Originally Posted by}}\) @dude
Yeah

For the x and y in the parenthesis you want it to have the opposite sign

\((x\color{red}{+}1)^2+(y\color{red}{+}2)^2\) -> (-1,-2)

For the right side of the equation
You had =7

The radius is 7 but the equation is \(r^2\)

So, just square 7
\(\color{#0cbb34}{\text{End of Quote}}\)
Ohhhhhhhhhhh okay I get it now, Thank you!