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Mathematics 12 Online
Timmyspu:

Help

Timmyspu:

Convert:

When it's substitution you have to find one variable and plug it into the equation after you find the value for that variable.

Timmyspu:

ok

Convert:

Usually when you do this you would look at which variable is easier to find which depends on if the variable is isolated (on the other side of the equal sign) from the rest

Timmyspu:

ok

Convert:

Another thing you have to pay attention to is how easy the coefficient is to divide from the constant so you can avoid having to deal with fractions because that makes everything 100 times more complicated

Timmyspu:

ok

Convert:

So do you think you can do this now or would you like me to do a step by step of the 1st problem?

Timmyspu:

step by step pls

Convert:

So in the 1st problem this is fairly easy compared to the other ones because it already gives you the "y" 4x + 7y = 7 y = x + 1 Since you have the "y" variable you plug in what it is equal to into the 1st equation 4x + 7 ( x + 1 ) = 7 After this you would multiply out the parenthesis 4x + ( 7 * x ) + ( 7 * 1) = 7 You would then simplify and remove the parenthesis 4x + 7x + 7 = 7 After this you would add the like terms ( x's ) 11x + 7 = 7 Then you would subtract off both of the sides 11x + 7 = 7 - 7 -7 11x = 0 Then you would divide to get the "x" by itself and since anything divided by 0 is 0 the 0 would stay the same so x would equal 0. x= 0 After this you add in the "y" value from the beginning to the final answer: x = 0 ; y= x + 1

Convert:

It is the same overall for the rest of the problems

Timmyspu:

ok that makes sense thank you so much

Convert:

glad to help! :)

Convert:

Do you think you can do the rest on your own now?

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