Question

y = x^(ln(x))
What is y'

Answer 1

idk

Answer 2

\[y=(x)^{lnx}\]

Answer 3

y = x

Answer 4

You have to find y'

Answer 5

oh

Answer 6

@darkknight

Answer 7

yes

Answer 8

darkknight they suspended me from chat

Answer 9

yo Death plz don't spam the post
And Ashoka, this is Calc, so....
\[y=x^{lnx}\]
we take ln of both sides
\[\ln(y)=\ln(x ^{lnx})\]
\[1/y \times y' = \ln(x) \times \ln(x)\]
Use product rule
\[y' = \ln(x) \times 1/x + \ln(x) \times 1/x \times y\]
\[y'=2\ln(x)/x \times x ^{lnx}\]
(I plugged in x^ln(x) for y in the previous step

Answer 10

Okay, that makes a lot of sense, thanks darkknight!

Answer 11

np

Answer 12

i wont darkknight

Answer 13

sure you can