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Earth Sciences 6 Online
RodeWolf:

Half-lives Carbon 14 ------ 5730 years Uranium 235---- 713 million years Potassium 40---- 1.3 billion years 1. Scientists found a fossilized bone from an organism in a deep layer of rock. When they took the bone back to the lab they realized that the bone had only 12.5% of the total Carbon 14 left. Based on the amount of Carbon 14 left in the bone how old is the bone?

badgirlhope:

Ok so you would be tryna find a equation so you will be tryna solve for 0.5n so what would n equal

RodeWolf:

I am so lost rn I dunno at all we haven't been doing that *screaming*

badgirlhope:

ok so ill break it down for you

RodeWolf:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @badgirlhope ok so ill break it down for you \(\color{#0cbb34}{\text{End of Quote}}\) ok thxs

badgirlhope:

you can use the equation fraction remaining = 0.5n where n is # of half lives elapsed n=? fraction remaining = 1 - 0.612 = ?

badgirlhope:

so what would 1 - 0.612 equal

RodeWolf:

ok i got 0.388

badgirlhope:

yes that is correct so 0.388 = 0.5n

badgirlhope:

but that is not all

badgirlhope:

n=1.37 = the # of half lives

badgirlhope:

what would 1.37 x 5750 yrs equal

RodeWolf:

ok hold on

RodeWolf:

7877.5?

badgirlhope:

im not going to confuse you with all the steps so the answer would be 13305 years

RodeWolf:

gosh but was 7877.5 right?

jovanie:

i think so

badgirlhope:

If you would do this that answer would be wrong 0.20X=X%281%2F2%29%5E%28T%2F5730%29 0.20=%281%2F2%29%5E%28T%2F5730%29 log%281%2F2%2C%280.2%29%29=T%2F5730 T%2F5730=%28log%28%280.2%29%29%2Flog%28%280.5%29%29%29 T=5730%2A%28log%28%280.2%29%29%2Flog%28%280.5%29%29%29 T=5730%2A2.322 T=13305years

badgirlhope:

thats is why i didnt post it because it would confuse you but n=13305 years

RodeWolf:

gosh yeah thanks though appreciated

badgirlhope:

your welcome

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