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Mathematics 8 Online
bwright63:

Quadrilateral ABCD in the figure below represents a scaled-down model of a walkway around a historic site. Quadrilateral EFGH represents the actual walkway. ABCD is similar to EFGH. Two irregular similar quadrilaterals ABCD and EFGH are drawn. AB measures 6 inches, BC measures 3 inches, CD measures 3 inches and DA measures 4 inches. EF measures 72 feet. What is the total length, in feet, of the actual walkway?

XioGonz:

|dw:1607618816209:dw| Is this what it looks like?

bwright63:

yes

XioGonz:

First off, we know ABCD and EFGH are similar

XioGonz:

The only difference is they're scaled differently

XioGonz:

We know that the ratio between each corresponding segment will be the same.

XioGonz:

we also know that AB is 6 inches, and that EF is 72 feet

bwright63:

wait, so how do i find the sides on the bigger shape

XioGonz:

We have to use what we already know about the smaller shape to find the sides of the bigger one

bwright63:

hmm, so everything on the smaller shape is half of the bigger shape?

bwright63:

like if they divided the numbers in half

XioGonz:

Not quite,

XioGonz:

Okay, as I said earlier we know the ratio between each corresponding segment will be the same. and that EF is 72 feet, so the ratio is 144 (72/6 = 12, then 12 inches per foot) Meaning EF is 12 times longer (in feet) than AB is (in inches)...

XioGonz:

Are you following?

bwright63:

yes, so then GF would be 36 because it would also be 12 time longer then CB? because AB times 12 get you 72 which is EF

XioGonz:

Yeah, here: are the steps EF = 72 ft FG = 36 ft (3 * 12) GH = 36 ft (3 * 12) EH = 48 ft (4 * 12)

XioGonz:

So, now we know that the total length of the pathway is: 72 + 36 + 36 + 48 = 192 feet

bwright63:

oh, okay i get it now, thank you!

XioGonz:

Np! can I get a medal?

bwright63:

how do i do that

XioGonz:

Thank you!

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