Solve the system y = -x + 7 and y = -0.5(x - 3)^2 + 8
Ok so first off do you have a algebraic calculator
yes
do you need help ?
\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9 do you need help ? \(\color{#0cbb34}{\text{End of Quote}}\) yes please
do you know the substitution method ?
or elimination method ?
what you wan or need use here ?
old question, but will respond so this can be closed y = -x + 7 and y = -0.5(x - 3)^2 + 8 you can set them equal to each other to get -x + 7 = -0.5(x-3)^2 + 8 you can expand the right side using FOIL, then combine the constant terms -x + 7 = -0.5x^2 + 3x + 3.5 from there, you can add x - 7 to both sides, to get 0 on one side 0.5x^2 - 4x + 3.5 = 0 and use the quadratic formula to get your possible x-values. from there, plug x into the equation to find the corresponding y-values.
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