Geometry?
hint: XYZ is the shared overlapping angle between the two triangles
this is what I put in: The congruence theorem would be Side-Angle-Side proving triangle XBY is congruent to triangle ZAY.
for 2b.
We're already given \( \angle X \cong \angle Z\) and \( \overline{XY} \cong \overline{ZY}\) That takes care of the "A" and "S" respectively As mentioned with the overlapping angles, if we knew that \(\angle XYB \cong \angle ZYA\), then we would have enough information to use ASA.
Once we've proven \(\triangle XBY \cong \triangle ZAY\), we use CPCTC to lead to \(\overline{AZ} \cong \overline{BX}\) CPCTC = corresponding parts of congruent triangles are congruent
oh its ASA and not SAS?
correct
|dw:1607649552118:dw|
We know angle X is congruent to angle Z |dw:1607649621800:dw| So that's one "A" of ASA
and we know that XY and YZ are the same length That's "S" of ASA |dw:1607649695012:dw|
If we knew that angle XYB = angle ZYA then we have enough for ASA |dw:1607649744356:dw|
note how the marked sides (the sides with the double tickmarks) are between the marked angles |dw:1607649823980:dw| So that tells us we aren't using AAS but instead we use ASA
ok thank you @jimthompson5910
No problem
do you have time for 2 more? lol if not that ok.
sure
how far did you get with problem 1?
I have only done the given's, I haven't got farther than that I am stuck
What do you notice about ZX?
its in the middle but also a bisector. Is that what you mean?
it might help to break up the triangles like so |dw:1607650121667:dw|
Would you agree that ZX = ZX?
yes by reflexive prpperty
property*
yes
|dw:1607650229356:dw|
Do we have enough to prove these triangles congruent?
yes by SAS
yep
But that was in the given already that those two trangles are congruent
Then by CPCTC, we know that angle WXZ = angle YXZ |dw:1607650308530:dw|
but those angles I just marked also add up to 180 since angle WXY of the original drawing is a straight angle let p = measure of angle WXZ = measure of angle YXZ You need to solve p+p = 180
by triangle sum theorem
what do you get when you solve for p in the equation p+p = 180
ill be honest idk im lost...
p+p turns into 2p, correct?
oh.. yes sorry
so if 2p = 180, then p = ??
i am this far so far
p = 90
oh so right angle
that takes care of the "perpendicular" part
to prove the "bisector" part, you need to show that WX = XY
since "bisect" means "cut in half" or "cut into two smaller equal pieces"
yes, sorry I went afk but im back
its ok
so how can you show that WX = XY ?
transitive?
go back to this drawing |dw:1607655359247:dw|
We've proven the triangles to be congruent, so we know that the corresponding pieces WX and XY are the same length |dw:1607655379463:dw|
Because WX = XY, this means segment ZX bisects (cuts in half) segment WY
oh by the HL theorem
no we proved the triangles congruent by SAS
yes but isnt the last proof HL
the bisector one
you only use HL if you know the triangles are right triangles But we already proved them to be congruent using SAS. So using HL is unnecessary
ok thank you
that is all I needed, I went ahead and did the other one, thank you so much for your help
You're welcome
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