Question

Algebra Question!

Answer 1

do you remember what each term is?

Answer 2

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Aqual
do you remember what each term is?
\(\color{#0cbb34}{\text{End of Quote}}\)
The identities? I don't know the terms...

Answer 3

Hints:
\(\large \cot(x) = \frac{1}{\tan(x)}\)
\(\large \sec(x) = \frac{1}{\cos(x)}\)
\(\large \tan^2(x)+1=\sec^2(x)\)

More trig identities can be found here
https://tutorial.math.lamar.edu/pdf/Trig_Cheat_Sheet.pdf

Answer 4

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jimthompson5910
Hints:
\(\large \cot(x) = \frac{1}{\tan(x)}\)
\(\large \sec(x) = \frac{1}{\cos(x)}\)
\(\large \tan^2(x)+1=\sec^2(x)\)

More trig identities can be found here
https://tutorial.math.lamar.edu/pdf/Trig_Cheat_Sheet.pdf
\(\color{#0cbb34}{\text{End of Quote}}\)
Oh! I have those!

Answer 5

Let me know what you get

Answer 6

I got 0 somehow....

Answer 7

0 is incorrect

Answer 8

Another hint:

\(\large \frac{\tan(x)}{\cot(x)}-\frac{\sec(x)}{\cos(x)}=\tan(x)*\frac{1}{\cot(x)}-\sec(x)*\frac{1}{\cos(x)}\)

\(\large \frac{\tan(x)}{\cot(x)}-\frac{\sec(x)}{\cos(x)}=\tan(x)*\tan(x)-\sec(x)*\sec(x)\)

\(\large \frac{\tan(x)}{\cot(x)}-\frac{\sec(x)}{\cos(x)}=\tan^2(x)-\sec^2(x)\)

This can be simplified further