Question

can someone help me answer this, please

Answer 1

@Imagine @justus

Answer 2

@jhonyy9 @jesuslopez1

Answer 3

@sammixboo

Answer 4

@Vocaloid

Answer 5

yo someone help me i'm being timed rn

Answer 6

@mxddi3

Answer 7

@563blackghost

Answer 8

The LCM of the equation is correct. It being \(\bf{2x(4x+3)}\) but it was applied to the parenthesis incorrectly.

\(\large\bf{2x(4x+3) \times (\frac{-5}{4x+3} + \frac{3}{2x} = \frac{17}{8x^{2}+6x})}\)

You apply the LCM to each fraction.

\(\large\bf{(\frac{-5}{4x+3} \times 2x(4x+3)) + (\frac{3}{2x} \times 2x(4x+3)) = \frac{17}{8x^{2}+6x} \times 2x(4x+3)}\)

Simplify and you'll see how it differs to `Step 2`.

Answer 9

@563blackghost thank you so much for your help!!!!

Answer 10

ah no problem cx

Answer 11

I have another question will you help me answer it?

Answer 12

i can look at it, sure cx

Answer 13

I can't see the whole answer for the 1st question

Answer 14

\(\bf{(\frac{-5}{4x+3} \times 2x(4x+3)) + (\frac{3}{2x} \times 2x(4x+3)) = \frac{17}{8x^{2}+6x} \times 2x(4x+3)}\)

im rusty with my latex x.x its been a while.

Answer 15

lol thank you
do I just copy paste the answer?

Answer 16

well i would suggest putting it into your own words. I mean, do you understand the explanation I gave you?

Answer 17

yes I do

Answer 18

i'll close this post and open an another one

Answer 19

I mean it's basically an error in the distribution of the LCM.

\(\bf{Distributive ~Property}\)

\(\bf{a(b+c)=ab + bc}\)

Answer 20

welp

ab + ac*

Answer 21

ok thank you!

Answer 22

ur second question?

Answer 23

I'll post it in an another question and will mention you

Answer 24

okay