A copper cylinder has a mass of 76.7g and a specific heat of 0.092cal/gоC. It is heated to 86.0оC and then put in 68.8g of turpentine whose temperature is 19.0оC. The final temperature of the mixture is 32.0оC. What is the specific heat of the turpentine?

Question

Vocaloid · Answer

set up the heat equation twice$$q = mC(T_{f}-T_{i})$$where q is the heat being transferred, m is mass, C is specific heat, Tf is final temperature, and Ti is initial temperature

once for the copper, and again for the turpentine

since they're both being mixed together, Tf for both is the temperature of the mixture, 32.0 degrees C. heat is conserved (any heat lost by the copper is gained by the turpentine) so you can set both q's equal to each other.

plug in the appropriate quantities and solve for C (on the turpentine equation)