Question

A 1.00 kg piece of aluminum metal at 90.0 °C is placed in 4.00 liters (= 4.00 kg) of water at 25.0 °C. Determine the final temperature (Tf).

Answer 1

There wasn't a thermodynamics section.....

Answer 2

\(\Delta Q = m_1 ~ c_1 ~ \Delta T_1 = m_2 ~ c_2 ~ \Delta T_2\)

Answer 3

That's the formula?

Answer 4

\( 1 * c_{Al} * (90 - T_f) = 4 * c_{H_2 O} * (T_f - 25)\)

Answer 5

it's not the answer, but in any engineering or physics pursuit, it's the Newtonian formula that makes sense and that is backed up by common sense.

Answer 6

Ok thank you, I will look into that

Answer 7

I think you are right, btw: there should be a Thermo section.

Answer 8

Yea lol