Triangle PQR is transformed to triangle P′Q′R′. Triangle PQR has vertices P(4, 0), Q(0, −4), and R(−8, −4). Triangle P′Q′R′ has vertices P′(1, 0), Q′(0, −1), and R′(−2, −1). Plot triangles PQR and P′Q′R′ on your own coordinate grid. Part A: What is the scale factor of the dilation that transforms triangle PQR to triangle P′Q′R′? Explain your answer. (4 points) Part B: Write the coordinates of triangle P′′Q′′R′′ obtained after P′Q′R′ is reflected about the y-axis. (4 points) Part C: Are the two triangles PQR and P′'Q′'R′' congruent? Explain your answer. (2 points)
@darkknight
have u plotted them yet?
yes
im stuck on part B
alr if u already plotted the 2 triangles can u upload so i can get the visual? Easier for both of us so i don't have to plot again
actually nvm i got it it won't tak elong
ok
alr i plotted these. so Im going to assume you have P′Q′R' triangle plotted already? To reflect about the y-axis do you know what to do?
yes
yes for the triangle being plotted or reflecting about y-axis? Imagine i have a shape like this|dw:1608753952483:dw| and I want to reflect about the y-axis |dw:1608753975165:dw| (That line I drew represents the y-axis) So the reflective shape will look like this: |dw:1608754013198:dw| (sort of not to scale) Basically what happened is that all the y coordinates stayed the same, but the x coordinates are reflected, since the y-axis is x=0, then all the x coordinates are reflected by x=0, so if one of the original x coordinates was -2 it would be +2, if one was 5 the reflected about x=0 version would be -5
So if you reflect P′Q′R′ across the y-axis (x=0) all the y coordinates (the 3 y-coordinates) will stay the same and the x-coordinates will be negative to positive or positive to negative
ok, thank you, now I understand.
No problem, need help on part 3?
sure.
alr, so 2 triangles are always congruent if we apply transformations such as reflection, translation, and rotation. Think about it? If you turn a shape a few degrees it still has the congruency right? What about it you reflect it? still it does. If you move the shape it should still have congruency. Dilating a shape changes the size so no congruency if that happens. Based off of the transformations we did, what do you think?
Key point, PQR and P′'Q′'R′' are these 2 triangles congruent? think about the transformations we did from PQR and P'Q'R' and from P'Q'R' to P''Q''R''
I think the 2 triangles are congruent because P"Q"R is just being reflected off of P'Q'R'. The shape dones't change.
Im helping him lol, give me a min
Almost correct. Triangle PQR has vertices P(4, 0), Q(0, −4), and R(−8, −4). Triangle P′Q′R′ has vertices P′(1, 0), Q′(0, −1), and R′(−2, −1). If you look at the original (THE original) triangle it is actually dilated by 4 times less, do you see that?
yes
Okay, so we have 1 dilation, u read this? \(\color{#0cbb34}{\text{Originally Posted by}}\) darkknight alr, so 2 triangles are always congruent if we apply transformations such as reflection, translation, and rotation. Think about it? If you turn a shape a few degrees it still has the congruency right? What about it you reflect it? still it does. If you move the shape it should still have congruency. Dilating a shape changes the size so no congruency if that happens. Based off of the transformations we did, what do you think? \(\color{#0cbb34}{\text{End of Quote}}\)
yes
ignore that user, so you think they are congruent now?
.... ummmm yes
" Dilating a shape changes the size so no congruency if that happens..." We dilated the shape from PQR to P'Q'R' Therefore the shape is? congruent or not congruent?
"two figures or objects are congruent if they have the same shape and size" dilating the shape changes the size
the shape is not congrunet
Are the two triangles PQR and P′'Q′'R′' congruent? You found them not to be. and I'll assume you know why they aren't?
yes, because the shape changed size and if it changes sizes then it's not congruent.
Perfect, have a good day : )
thank you
good job @darkknight
Thanks
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