Question

A freight train leaving a train yard must exert a force of 2.53 x 106N in order to increase its speed from rest to 17.0 m/s. During this process, the train must do 1.10 x 109J of work. How far does the train travel?

Answer 1

So what is the first thing we need to do.

Answer 2

2.53*106N?

Answer 3

Yes that is the first thing we have to do. What is the second thing?

Answer 4

times the answer by 17.0 m/s?

Answer 5

Yes correct so what is the awnser?

Answer 6

Workdone = 1110000000 J

Force = 2530000 N

Workdone = force × distance

1110000000 = 2530000 × distance

Distance = 1110000000 ÷ 2530000

Distance = 438.735m

Distance = 438.74m

The distance traveled by the freight train in other to increase it's speed from rest to 17m/s is 438.74m

Answer 7

Please let me figure it out without telling me the answer

Answer 8

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Maxine
Please let me figure it out without telling me the answer
\(\color{#0cbb34}{\text{End of Quote}}\)
if you wanted to figure it out on your own then why even post the question

Answer 9

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Timmyspu
Yes correct so what is the awnser?
\(\color{#0cbb34}{\text{End of Quote}}\)
4559.06 is what I got.

Answer 10

\(\color{#0cbb34}{\text{Originally Posted by}}\) @imbadkidjenna
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Maxine
Please let me figure it out without telling me the answer
\(\color{#0cbb34}{\text{End of Quote}}\)
if you wanted to figure it out on your own then why even post the question
\(\color{#0cbb34}{\text{End of Quote}}\)
I mean with others talking me through the problem.

Answer 11

Good job you are correct awnser.

Answer 12

have*

Answer 13

Then would i do 1.10*109?

Answer 14

Yes you would

Answer 15

that would be 119.9

Answer 16

yes

Answer 17

Then would I add them together?

Answer 18

yes

Answer 19

4678.96 is what I got.

Answer 20

Good job

Answer 21

Thank you. I also have more problems like this.

Answer 22

ok

Answer 23

I can help you with more