Question

A triangle has a base of 2^3 units and a height of 2^4 units. What is the area of the​ triangle? Write your answer as a power of 2

Answer 1

Do you know the formula for the area of a triangle?

Answer 2

https://www.khanacademy.org/math/cc-sixth-grade-math/cc-6th-geometry-topic/cc-6th-area-triangle/a/area-of-triangle

Answer 3

here you go the formula

Answer 4

@supie

Answer 5

So, we have to do \(Base*Hight\)

Correct?

Answer 6

@jimthompson5910

Answer 7

\(\color{#0cbb34}{\text{Originally Posted by}}\) @supie
So, we have to do \(Base*Hight\)

Correct?
\(\color{#0cbb34}{\text{End of Quote}}\)
I'm pretty sure

Answer 8

who is that you just @?

Answer 9

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Jennaofcbaby
who is that you just @?
\(\color{#0cbb34}{\text{End of Quote}}\)
A smart guy.

Answer 10

\(\color{#0cbb34}{\text{Originally Posted by}}\) @supie
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Jennaofcbaby
who is that you just @?
\(\color{#0cbb34}{\text{End of Quote}}\)
A smart guy.
\(\color{#0cbb34}{\text{End of Quote}}\)
Oh cool.

Answer 11

Oop imma get an A with him.

Answer 12

You're close, but the area of a triangle is \(\large \frac{\text{base*height}}{2}\)

Answer 13

Okay but i need it written in power of 2

Answer 14

If that's it bc im not good at math

Answer 15

If base = 2^3 and height = 2^4, then we can say:

\(\large \text{area} = \frac{\text{base*height}}{2}\)

\(\large \text{area} = \frac{2^3*2^4}{2}\)

\(\large \text{area} = \frac{2^3*2^4}{2^1}\)

What's the next step from here?

Answer 16

to be honest I really don't know but what it says it's just I have to write it in the power to

Answer 17

@jimthompson5910

Answer 18

Recall that we have these exponent rules
\(\large a^b*a^c = a^{b+c}\)
and
\(\large \frac{a^b}{a^c} = a^{b-c}\)
which I'll refer to as rule 1 and rule 2 respectively

Using those rules leads to the following:
\(\large \text{area} = \frac{2^3*2^4}{2^1}\)

\(\large \text{area} = \frac{2^{3+4}}{2^1} .... \text{ use rule 1}\)

\(\large \text{area} = \frac{2^7}{2^1}\)

\(\large \text{area} = 2^{7-1} .... \text{ use rule 2}\)

There's one more step after this.

Answer 19

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jimthompson5910
Recall that we have these exponent rules
\(\large a^b*a^c = a^{b+c}\)
and
\(\large \frac{a^b}{a^c} = a^{b-c}\)
which I'll refer to as rule 1 and rule 2 respectively

Using those rules leads to the following:
\(\large \text{area} = \frac{2^3*2^4}{2^1}\)

\(\large \text{area} = \frac{2^{3+4}}{2^1} .... \text{ use rule 1}\)

\(\large \text{area} = \frac{2^7}{2^1}\)

\(\large \text{area} = 2^{7-1} .... \text{ use rule 2}\)

There's one more step after this.
\(\color{#0cbb34}{\text{End of Quote}}\)
Look at the ss i sent that's what i see

Answer 20

I've looked at it. You just need to simplify \(\large 2^{7-1}\) at this point.

Answer 21

So what is it?

Answer 22

Simplifying the 7-1 leads to 6, so \(\large 2^{7-1} = 2^6\)

Answer 23

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jimthompson5910
Simplifying the 7-1 leads to 6, so \(\large 2^{7-1} = 2^6\)
\(\color{#0cbb34}{\text{End of Quote}}\)
In what unit? square units cubic units or just units

Answer 24

areas always deal with square units
eg: square cm, square inches, etc

Answer 25

Okay thanks for your help!

Answer 26

You're welcome