Question

PLEASE HELP!!!

Are real numbers closed under multiplication, or not closed?

Answer 1

Thank you

Answer 2

\(\color{#0cbb34}{\text{Originally Posted by}}\) @n0mn0mlemon
Thank you
\(\color{#0cbb34}{\text{End of Quote}}\)
np

Answer 3

Real numbers are closed under multiplication because
(real number)*(real number) = real number

In terms of symbols, we can say
x*y = z
where x,y,z are real numbers

Answer 4

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jimthompson5910
Real numbers are closed under multiplication because
(real number)*(real number) = real number

In terms of symbols, we can say
x*y = z
where x,y,z are real numbers
\(\color{#0cbb34}{\text{End of Quote}}\)
you're giving out the answer they won't accept it

Answer 5

right @Hero

Answer 6

I am so confused

Answer 7

@jimthompson5910 is right. Listen to him

Answer 8

I wasn't sure how to answer. Also, you stated "not closed" which is also giving the answer.

Answer 9

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jimthompson5910
I wasn't sure how to answer. Also, you stated "not closed" which is also giving the answer.
\(\color{#0cbb34}{\text{End of Quote}}\)
no I didn't I was thinking not looking it up on google

Answer 10

Okay, well thanks

Answer 11

\(\color{#0cbb34}{\text{Originally Posted by}}\) @n0mn0mlemon
Okay, well thanks
\(\color{#0cbb34}{\text{End of Quote}}\)
np

Answer 12

Well when someone outright gives the wrong answer, someone like @jimthompson5910 has to come along and save the day.

Answer 13

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Hero
Well when someone outright gives the wrong answer, someone like @jimthompson5910 has to come along and save the day.
\(\color{#0cbb34}{\text{End of Quote}}\)
I'm sorry I should get a warning

Answer 14

I have another question.
Are irrational numbers closed under division?

Answer 15

\(\color{#0cbb34}{\text{Originally Posted by}}\) @n0mn0mlemon
I have another question.
Are irrational numbers closed under division?
\(\color{#0cbb34}{\text{End of Quote}}\)
that depends on the number of questions but @jimthompson5910 can. you help him pls

Answer 16

Consider dividing \(\large \sqrt{32}\) over \(\large \sqrt{8}\). Do you get an irrational number?

The rule \(\large \frac{\sqrt{x}}{\sqrt{y}} = \sqrt{\frac{x}{y}}\) can be used, but it's not mandatory.