Question

I have a question

Answer 1

I don't understan how to do this

Answer 2

so distance formula is a2 + b2 = c2

Answer 3

midpoint formula is - [(x1 + x2)/2, (y1 + y2)/2]

Answer 4

you have to rewrite the Pythagorean theorem as d=√((x_2-x_1)²+(y_2-y_1)²) to find the distance between any two points.

Answer 5

\(\color{#0cbb34}{\text{Originally Posted by}}\) @4evablood
midpoint formula is - [(x1 + x2)/2, (y1 + y2)/2]
\(\color{#0cbb34}{\text{End of Quote}}\)
so how would I find c

Answer 6

\(\color{#0cbb34}{\text{Originally Posted by}}\) @carlosesgirl
\(\color{#0cbb34}{\text{Originally Posted by}}\) @4evablood
midpoint formula is - [(x1 + x2)/2, (y1 + y2)/2]
\(\color{#0cbb34}{\text{End of Quote}}\)
so how would I find c
\(\color{#0cbb34}{\text{End of Quote}}\)
ok so when u plug in the numbers into the formula u square each number even c

Answer 7

no, actually the distance formula is \[d=\sqrt{(x2-x1)^2}+(y2-y1)^2\]
so do that first, and then they told you midpoint and then slope is just
\[\frac{ y2-y1 }{ x2-x1 }\]

Answer 8

\(\color{#0cbb34}{\text{Originally Posted by}}\) @mxddi3
no, actually the distance formula is \[d=\sqrt{(x2-x1)^2}+(y2-y1)^2\]
so do that first, and then they told you midpoint and then slope is just
\[\frac{ y2-y1 }{ x2-x1 }\]
\(\color{#0cbb34}{\text{End of Quote}}\)
thats the same thing i said

Answer 9

\(\color{#0cbb34}{\text{Originally Posted by}}\) @mxddi3
no, actually the distance formula is \[d=\sqrt{(x2-x1)^2}+(y2-y1)^2\]
so do that first, and then they told you midpoint and then slope is just
\[\frac{ y2-y1 }{ x2-x1 }\]
\(\color{#0cbb34}{\text{End of Quote}}\)
but I only have two numbers her

Answer 10

\(\color{#0cbb34}{\text{Originally Posted by}}\) @4evablood
so distance formula is a2 + b2 = c2
\(\color{#0cbb34}{\text{End of Quote}}\)
no you said this, and this is the pythagorean theorem

Answer 11

\(\color{#0cbb34}{\text{Originally Posted by}}\) @carlosesgirl
\(\color{#0cbb34}{\text{Originally Posted by}}\) @mxddi3
no, actually the distance formula is \[d=\sqrt{(x2-x1)^2}+(y2-y1)^2\]
so do that first, and then they told you midpoint and then slope is just
\[\frac{ y2-y1 }{ x2-x1 }\]
\(\color{#0cbb34}{\text{End of Quote}}\)
but I only have two numbers her
\(\color{#0cbb34}{\text{End of Quote}}\)
the number from each points plug them into the equation

Answer 12

\(\color{#0cbb34}{\text{Originally Posted by}}\) @4evablood
\(\color{#0cbb34}{\text{Originally Posted by}}\) @carlosesgirl
\(\color{#0cbb34}{\text{Originally Posted by}}\) @mxddi3
no, actually the distance formula is \[d=\sqrt{(x2-x1)^2}+(y2-y1)^2\]
so do that first, and then they told you midpoint and then slope is just
\[\frac{ y2-y1 }{ x2-x1 }\]
\(\color{#0cbb34}{\text{End of Quote}}\)
but I only have two numbers her
\(\color{#0cbb34}{\text{End of Quote}}\)
the number from each points plug them into the equation
\(\color{#0cbb34}{\text{End of Quote}}\)
makes sense

Answer 13

\(\color{#0cbb34}{\text{Originally Posted by}}\) @carlosesgirl
\(\color{#0cbb34}{\text{Originally Posted by}}\) @4evablood
\(\color{#0cbb34}{\text{Originally Posted by}}\) @carlosesgirl
\(\color{#0cbb34}{\text{Originally Posted by}}\) @mxddi3
no, actually the distance formula is \[d=\sqrt{(x2-x1)^2}+(y2-y1)^2\]
so do that first, and then they told you midpoint and then slope is just
\[\frac{ y2-y1 }{ x2-x1 }\]
\(\color{#0cbb34}{\text{End of Quote}}\)
but I only have two numbers her
\(\color{#0cbb34}{\text{End of Quote}}\)
the number from each points plug them into the equation
\(\color{#0cbb34}{\text{End of Quote}}\)
makes sense
\(\color{#0cbb34}{\text{End of Quote}}\)
yeah

Answer 14

ok so you have (-3,2) and (7,6) so for slope, you do \[\frac{ 6-2 }{ 7- (-3) }\]

Answer 15

midpoint:
\[\frac{ -3+7 }{ 2 }, \frac{ 2+6 }{ 2 }\]

Answer 16

\(\color{#0cbb34}{\text{Originally Posted by}}\) @mxddi3
ok so you have (-3,2) and (7,6) so for slope, you do \[\frac{ 6-2 }{ 7- (-3) }\]
\(\color{#0cbb34}{\text{End of Quote}}\)
so would the answer here be 0.4

Answer 17

well it's slope of a line,so we write it as a fraction and it can be simplified as well (:

Answer 18

\(\color{#0cbb34}{\text{Originally Posted by}}\) @mxddi3
well it's slope of a line,so we write it as a fraction and it can be simplified as well (:
\(\color{#0cbb34}{\text{End of Quote}}\)
so what is 0.4 as a fraction

Answer 19

4/10
but you have to simplify it,asi said. So divide the top and bottom by their GCF, 2.

Answer 20

\(\color{#0cbb34}{\text{Originally Posted by}}\) @mxddi3
4/10
but you have to simplify it,asi said. So divide the top and bottom by their GCF, 2.
\(\color{#0cbb34}{\text{End of Quote}}\)
so it would be 2/5

Answer 21

Mhm, yes. Now do the midpoint and distance.

Answer 22

\(\color{#0cbb34}{\text{Originally Posted by}}\) @mxddi3
midpoint:
\[\frac{ -3+7 }{ 2 }, \frac{ 2+6 }{ 2 }\]
\(\color{#0cbb34}{\text{End of Quote}}\)
would you add these

Answer 23

\(\color{#0cbb34}{\text{Originally Posted by}}\) @carlosesgirl
\(\color{#0cbb34}{\text{Originally Posted by}}\) @mxddi3
midpoint:
\[\frac{ -3+7 }{ 2 }, \frac{ 2+6 }{ 2 }\]
\(\color{#0cbb34}{\text{End of Quote}}\)
would you add these
\(\color{#0cbb34}{\text{End of Quote}}\)
or would it be 2/4

Answer 24

so your first pint is going to be the -3+7/2. so what is -3+7? Take that answer and divide it by 2 to get your x coordinate. and then do the same for the other one to get your y. So yes, it'd be (2,4) with those

Answer 25

so the capital M is where I put it

Answer 26

Yes, the d is distance, M is midpoint, and m is slope

Answer 27

\(\color{#0cbb34}{\text{Originally Posted by}}\) @mxddi3
Yes, the d is distance, M is midpoint, and m is slope
\(\color{#0cbb34}{\text{End of Quote}}\)
so what do I do to find distance

Answer 28

the distance formula is \[d=\sqrt{(x2-x1)^2}+(y2-y1)^2\]
so we have (-3,2) and (7,6) and we write it by plugging in the values. So, x1=-3 x2=7 y1=2 and y2=6

Answer 29

what?