Question

how do you find distance of two points on a coordinate plane

Answer 1

Do you know what a coordinate plane is?

Answer 2

\(\color{#0cbb34}{\text{Originally Posted by}}\) @IMURDADDY4EVER
Do you know what a coordinate plane is?
\(\color{#0cbb34}{\text{End of Quote}}\)
yes I do

Answer 3

"Derived from the Pythagorean Theorem, the distance formula is used to find the distance between two points in the plane. "

Answer 4

Do you know what the Pythagorean Theorem is?

Answer 5

well i found something from Google Derived from the Pythagorean Theorem, the distance formula is used to find the distance between two points in the plane. The Pythagorean Theorem, a2+b2=c2 a 2 + b 2 = c 2 , is based on a right triangle where a and b are the lengths of the legs adjacent to the right angle, and c is the length of the hypotenuse.

Answer 6

\(\color{#0cbb34}{\text{Originally Posted by}}\) @4evablood
"Derived from the Pythagorean Theorem, the distance formula is used to find the distance between two points in the plane. "
\(\color{#0cbb34}{\text{End of Quote}}\)
I have these points

Answer 7

\(\color{#0cbb34}{\text{Originally Posted by}}\) @IMURDADDY4EVER
Do you know what the Pythagorean Theorem is?
\(\color{#0cbb34}{\text{End of Quote}}\)
yes I do

Answer 8

\(\color{#0cbb34}{\text{Originally Posted by}}\) @nalaynana
well i found something from Google Derived from the Pythagorean Theorem, the distance formula is used to find the distance between two points in the plane. The Pythagorean Theorem, a2+b2=c2 a 2 + b 2 = c 2 , is based on a right triangle where a and b are the lengths of the legs adjacent to the right angle, and c is the length of the hypotenuse.
\(\color{#0cbb34}{\text{End of Quote}}\)
thanks but I still don't get it

Answer 9

i told you, the distance formula is \[d=\sqrt{(x2-x1)^2}+(y2-y1)^2\]

just plug in the x and y values from your ordered pair.

Answer 10

Your going to find endpoints (x1,y1) and (x2,y2) using the formula \[d = √ ( x 2 − x 1 ) 2 + ( y 2 − y 1 ) 2\]

Answer 11

\(\color{#0cbb34}{\text{Originally Posted by}}\) @IMURDADDY4EVER
Your going to find endpoints (x1,y1) and (x2,y2) using the formula \[d = √ ( x 2 − x 1 ) 2 + ( y 2 − y 1 ) 2\]
\(\color{#0cbb34}{\text{End of Quote}}\)
How are you gonna copy maddie? smh

Answer 12

\(\color{#0cbb34}{\text{Originally Posted by}}\) @mxddi3
i told you, the distance formula is \[d=\sqrt{(x2-x1)^2}+(y2-y1)^2\]

just plug in the x and y values from your ordered pair.
\(\color{#0cbb34}{\text{End of Quote}}\)
I got 80

Answer 13

\(\color{#0cbb34}{\text{Originally Posted by}}\) @MxxnLight
\(\color{#0cbb34}{\text{Originally Posted by}}\) @IMURDADDY4EVER
Your going to find endpoints (x1,y1) and (x2,y2) using the formula \[d = √ ( x 2 − x 1 ) 2 + ( y 2 − y 1 ) 2\]
\(\color{#0cbb34}{\text{End of Quote}}\)
How are you gonna copy maddie? smh
\(\color{#0cbb34}{\text{End of Quote}}\)
I was typing it. I didnt see she put that there. ALso, I was helping them but people like to take over but ian trippin doe

Answer 14

\(\color{#0cbb34}{\text{Originally Posted by}}\) @IMURDADDY4EVER
\(\color{#0cbb34}{\text{Originally Posted by}}\) @MxxnLight
\(\color{#0cbb34}{\text{Originally Posted by}}\) @IMURDADDY4EVER
Your going to find endpoints (x1,y1) and (x2,y2) using the formula \[d = √ ( x 2 − x 1 ) 2 + ( y 2 − y 1 ) 2\]
\(\color{#0cbb34}{\text{End of Quote}}\)
How are you gonna copy maddie? smh
\(\color{#0cbb34}{\text{End of Quote}}\)
I was typing it. I didnt see she put that there. ALso, I was helping them but people like to take over but ian trippin doe
\(\color{#0cbb34}{\text{End of Quote}}\)
Mhm. e.e

Answer 15

Well, i don't know your ordered pairs so i cant say.

also, i wasnt taking over, i was helping them on their last post and then they made this one. And keep comments related to the post please (:

Answer 16

\(\color{#0cbb34}{\text{Originally Posted by}}\) @mxddi3
Well, i don't know your ordered pairs so i cant say.

also, i wasnt taking over, i was helping them on their last post and then they made this one. And keep comments related to the post please (:
\(\color{#0cbb34}{\text{End of Quote}}\)
Don't tell only me that

Answer 17

Can you tell me the ordered pairs that you have, please?

Answer 18

\(\color{#0cbb34}{\text{Originally Posted by}}\) @mxddi3
Can you tell me the ordered pairs that you have, please?
\(\color{#0cbb34}{\text{End of Quote}}\)
49,36 for 7,6 and then I got -9,4

Answer 19

is it the same ordered pairs from last time. i dont remember the first one, it was like (3,2) i think and (7,6). These ones?

Answer 20

\(\color{#0cbb34}{\text{Originally Posted by}}\) @mxddi3
is it the same ordered pairs from last time. i dont remember the first one, it was like (3,2) i think and (7,6). These ones?
\(\color{#0cbb34}{\text{End of Quote}}\)
yes and when I squared then I got those answers

Answer 21

ok so first you have to do x2-x1 and THEN square it, so for the x, (7- (-3))^2 did you do that ?

Answer 22

\(\color{#0cbb34}{\text{Originally Posted by}}\) @mxddi3
ok so first you have to do x2-x1 and THEN square it, so for the x, (7- (-3))^2 did you do that ?
\(\color{#0cbb34}{\text{End of Quote}}\)
no I did it the other way I did the two numbers together

Answer 23

no, you have to follow the steps as they are written, please use the distance formula that has been provided and then plug the x and y values into the formula (they will come from your ordered pairs)

Answer 24

\(\color{#0cbb34}{\text{Originally Posted by}}\) @carlosesgirl
\(\color{#0cbb34}{\text{Originally Posted by}}\) @mxddi3
ok so first you have to do x2-x1 and THEN square it, so for the x, (7- (-3))^2 did you do that ?
\(\color{#0cbb34}{\text{End of Quote}}\)
no I did it the other way I did the two numbers together
\(\color{#0cbb34}{\text{End of Quote}}\)
so 7^2 minus - 3^2

Answer 25

the distance formula is \[d=\sqrt{(x2-x1)^2}+(y2-y1)^2\]

so you have (-3,2) and (7,6) so write it out as
\[d=\sqrt{(7-(-3)^2}+(6-2)^2\]
NOW simplify.