Kaylib’s eye-level height is 48 ft above sea level, and Addison’s eye-level height is 85 and one-third ft above sea level. How much farther can Addison see to the horizon? Use the formula d = StartRoot StartFraction 3 h Over 2 EndFraction EndRoot, with d being the distance they can see in miles and h being their eye-level height in feet. StartRoot 2 EndRoot mi 2 StartRoot 2 EndRoot mi 14 StartRoot 2 EndRoot mi 28 StartRoot 2 EndRoot mi
Can you take a screenshot please?
I think its A
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Trap6a6yNino44 I think its A \(\color{#0cbb34}{\text{End of Quote}}\) Not quite,
brb
Me either but I try
ok
Ok so remember that we're using the formula \(d=\sqrt{\frac{3h}{2}}\)
yea
\(d=\sqrt{\frac{3h}{2}}\) \(d=\sqrt{\frac{48}{2}}\) \(d=\sqrt{72}\) \(d=\sqrt{\frac{3h}{2}}\) \(d=\sqrt{{}{2}}\) Yes?
Thanks
That's for Kaylib's eye level height
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Trap6a6yNino44 Thanks \(\color{#0cbb34}{\text{End of Quote}}\) thats not the answer
its not
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Trap6a6yNino44 its not \(\color{#0cbb34}{\text{End of Quote}}\) No, it's not.
We still have Addison's
ok
Then we get both of them and subtract
okay did det
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Trap6a6yNino44 okay did det \(\color{#0cbb34}{\text{End of Quote}}\) Ok, what did you get?
C
Its right
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