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For this problem, when you divide by exponents, the exponents subtract. For example x^2-x^1= x. You can separate each of the variables. Hope this helps
so it would be 4-12?
No you do that only for the x variable
So it would be 1- 3
-2
Yup that is correct. Now for the y variable only subtract the y's
Btw the x^-2 that you came up with is in the denominator. To make it positive, just put it in the numerator and it turns to x^2
20x^2
Yup, for the whole number we can simply view the problem as 20 divided by 4 so what is that?
5
Yup. So far we have 4x^2 for our answer. We just need to figure out the y and z now? What do you think the y is?
*I mean 5x^2
0
Why do you think y is 0?
because you cant do y^4 or y^2
Wait oops my bad I made a mistake. The x would be in the denominator to make it positive, so so far we have 5/x^2
Where did you get the y2 from?
the second part
In the screenshot you posted there is not y2
sorry i meant the 24
Here i'll just walk you through it. Hold up
so i ve solved this with you yesterday step by step
\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9 so i ve solved this with you yesterday step by step \(\color{#0cbb34}{\text{End of Quote}}\) this is a diffrent assiment
different assignment*
Steps: 1. we can treat 20/4 as a regular division problem so it is 5. So far we have the number 5 for our solution. 2. We do the x variable next. x^1 - x^3 = x^-2, but since this is negative, we drop it from the numerator to the denominator to make it positive, we want to make all exponents positive. So so far we have 5/x^2 as our answer. 3. We do the y variable next so y^4-y^1 = y^3. Since this is positive we keep it in the numerator. So far for our answer we have 5y^3/x^2. 4. Lastly we do the z variable. z^12-z^24 = z^-12 which is negative so we drop it down from the numerator to the denominator. Our final answer would be 5y^3/(x^2)(z^12) understand?
ok thank you
np. Do you understand how to do this though?
yes
Ok good 👍👍
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