Question

am I on the right track

Answer 1

??

Answer 2

yup

Answer 3

are you solving for \(x\)?

Answer 4

idek at this point

Answer 5

I believe so but not for sure

Answer 6

Ok so the first thing I would do is distribute
\(6(2x−11)+15=3x+12\)
\((6)(2x)+(6)(−11)+15=3x+12\)
\(12x+−66+15=3x+12\)

Then combine like terms:
\((12x)+(−66+15)=3x+12\)
\(12x+−51=3x+12\)
\(12x−51=3x+12\)

Then \(-3x\) from both sides
\(12x−51−3x=3x+12−3x\)
\(9x−51=12\)

Then we have to divide by \(9x\) to both sides
because all we have left is \(9x\)
\(\LARGE\frac{9x}{9}=\frac{69}{3}\)
So then \(\frac{9x}{9}\) cancels so all you have left is \(\frac{69}{3}\)
Simplify that, then you'll have your answer.

Answer 7

\(\color{#0cbb34}{\text{Originally Posted by}}\) @supie
Ok so the first thing I would do is distribute
\(6(2x−11)+15=3x+12\)
\((6)(2x)+(6)(−11)+15=3x+12\)
\(12x+−66+15=3x+12\)

Then combine like terms:
\((12x)+(−66+15)=3x+12\)
\(12x+−51=3x+12\)
\(12x−51=3x+12\)

Then \(-3x\) from both sides
\(12x−51−3x=3x+12−3x\)
\(9x−51=12\)

Then we have to divide by \(9x\) to both sides
because all we have left is \(9x\)
\(\LARGE\frac{9x}{9}=\frac{69}{3}\)
So then \(\frac{9x}{9}\) cancels so all you have left is \(\frac{69}{3}\)
Simplify that, then you'll have your answer.
\(\color{#0cbb34}{\text{End of Quote}}\)
dang

Answer 8

Yes @jakfishman?

Answer 9

hold on still processing XD

Answer 10

lol ok

Answer 11

yep u areee

Answer 12

@supie yes that helped

Answer 13

Alright good
Thanks for the medal!

Answer 14

np

Answer 15

if yo done can you close it cause i keep getting a notification