Which correctly shows how to use the GCF and the distributive property to find an expression equivalent to 45 + 72? A. 3 (15 + 24) B.9 (5 + 8 ) C. (5) (9) + (2) (36) D. (3) (15) + ( 8 ) (9)
btw this is for @Mathmachine2021
Oh ok then lmk if he cant solve it
hi
he couldn't post the question
Oh.. ok
OR SHE
it wont let me post stuff
im a boy :D
YAY! I GOT IT RIGHT THE FIRST TIME!
wha
You still need help? @Mathmachine2021
yes please
im stumped
Alright so basically we have to find the biggest number that can be divided evenly into 45 + 72
cause its: Greatest Common Factor
\(\LARGE\frac{45}{?}+\frac{72}{?}\) Which is the same thing as \(42÷?\) \(72÷?\) Any idea now? @Mathmachine2021
gcf
hmmmmmmm
Yes GCF = ``` >G-Greatest >Common >Multiple ``` Meaning that you have to find the biggest number that can be divided evenly into 45 + 72
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Mathmachine2021 hmmmmmmm \(\color{#0cbb34}{\text{End of Quote}}\) So any idea now?
no its kinda confusing
i leave this post to you guys now
\(\color{#0cbb34}{\text{Originally Posted by}}\) @P1n3appl31 i leave this post to you guys now \(\color{#0cbb34}{\text{End of Quote}}\) Alright
is supie rare
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Mathmachine2021 no its kinda confusing \(\color{#0cbb34}{\text{End of Quote}}\) So think back to this; \(\color{#0cbb34}{\text{Originally Posted by}}\) @supie \(\LARGE\frac{45}{?}+\frac{72}{?}\) Which is the same thing as \(42÷?\) \(72÷?\) \(\color{#0cbb34}{\text{End of Quote}}\) Lets start with 42, all you have to do is find what number can go into it evenly but it has to be the biggest number possible
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Mathmachine2021 is supie rare \(\color{#0cbb34}{\text{End of Quote}}\) Wym "rare"?
because u mathlete
\(\color{#0cbb34}{\text{Originally Posted by}}\) @supie \(\color{#0cbb34}{\text{Originally Posted by}}\) @Mathmachine2021 no its kinda confusing \(\color{#0cbb34}{\text{End of Quote}}\) So think back to this; \(\color{#0cbb34}{\text{Originally Posted by}}\) @supie \(\LARGE\frac{45}{?}+\frac{72}{?}\) Which is the same thing as \(42÷?\) \(72÷?\) \(\color{#0cbb34}{\text{End of Quote}}\) Lets start with 42, all you have to do is find what number can go into it evenly but it has to be the biggest number possible \(\color{#0cbb34}{\text{End of Quote}}\) why 42 ?
\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9 \(\color{#0cbb34}{\text{Originally Posted by}}\) @supie \(\color{#0cbb34}{\text{Originally Posted by}}\) @Mathmachine2021 no its kinda confusing \(\color{#0cbb34}{\text{End of Quote}}\) So think back to this; \(\color{#0cbb34}{\text{Originally Posted by}}\) @supie \(\LARGE\frac{45}{?}+\frac{72}{?}\) Which is the same thing as \(42÷?\) \(72÷?\) \(\color{#0cbb34}{\text{End of Quote}}\) Lets start with 42, all you have to do is find what number can go into it evenly but it has to be the biggest number possible \(\color{#0cbb34}{\text{End of Quote}}\) why 42 ? \(\color{#0cbb34}{\text{End of Quote}}\) Oh woops I misread I thought it said 43 when it really said 45 my mistake
42*
So what do you think ? which answer choice best fits? @Mathmachine2021
(We're just talking about 45 right now)
the way you are saying it is diffrent from they way i leanred so im kinda confused
Sorry I haven't done this \(\sf 3^{rd}\) grade work in a long time
oh ok
i just wanted the awnser because im doing a small quic rn
quiz*
Ok so \(\LARGE\frac{45}{5}+\frac{72}{8}\) Those are the biggest numbers that can be equally divided among the numerators That is just another way of writing \(\bf 45÷5\) and \(\bf 72 \div 8\) Now do you have any idea on what the answer is?
@Mathmachine2021???
no
im just not smart
congrats @supie good job
but thanks supie for trying to help me
\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9 congrats @supie good job \(\color{#0cbb34}{\text{End of Quote}}\) Thanks
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Mathmachine2021 but thanks supie for trying to help me \(\color{#0cbb34}{\text{End of Quote}}\) np
doz i need to close this now?
yeah sure
okay
IT IS NOW CLOSED
ok
thanks
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