Question

Geometry
for anybody who knows it ~.~ thx

Answer 1

Ok, to start off, which one do you think it is ?

Answer 2

m∠QST = 72°

Answer 3

\(\color{#0cbb34}{\text{Originally Posted by}}\) @nevaehhh
Ok, to start off, which one do you think it is ?
\(\color{#0cbb34}{\text{End of Quote}}\)
I thought it was B

Answer 4

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Hendrixapeals
Stronger is bryana
\(\color{#0cbb34}{\text{End of Quote}}\)
?

Answer 5

Lemme explain, Given:

m∠SQR = 108°,

Quadrilateral SQRT has diagonals QT and SR that intersect at point U,

We can tell that:

m∠QST = 72°

Answer 6

I think its really hard

Answer 7

\(\color{#0cbb34}{\text{Originally Posted by}}\) @xxxFrancisco14xx
I think its really hard
\(\color{#0cbb34}{\text{End of Quote}}\)
which is why I asked the question

Answer 8

\(\color{#0cbb34}{\text{Originally Posted by}}\) @xxxFrancisco14xx
Lemme explain, Given:

m∠SQR = 108°,

Quadrilateral SQRT has diagonals QT and SR that intersect at point U,

We can tell that:

m∠QST = 72°
\(\color{#0cbb34}{\text{End of Quote}}\)
106° not 108°

Answer 9

@jhonyy9 wym?

Answer 10

The answer is m∠SQR = 108°

Answer 11

It's <RQS not SQR just fyi-

Answer 12

pls re-read the text

Answer 13

okkokokokok

Answer 14

was it a direct answer?

Answer 15

The dude is clearly copying from another site, and is copying the wrong thing
please-

Answer 16

\(\color{#0cbb34}{\text{Originally Posted by}}\) @stranger2
\(\color{#0cbb34}{\text{Originally Posted by}}\) @nevaehhh
Ok, to start off, which one do you think it is ?
\(\color{#0cbb34}{\text{End of Quote}}\)
I thought it was B
\(\color{#0cbb34}{\text{End of Quote}}\)
I don't believe it's B, but I can walk you through it if you like~

Answer 17

\(\color{#0cbb34}{\text{Originally Posted by}}\) @nevaehhh
\(\color{#0cbb34}{\text{Originally Posted by}}\) @stranger2
\(\color{#0cbb34}{\text{Originally Posted by}}\) @nevaehhh
Ok, to start off, which one do you think it is ?
\(\color{#0cbb34}{\text{End of Quote}}\)
I thought it was B
\(\color{#0cbb34}{\text{End of Quote}}\)
I don't believe it's B, but I can walk you through it if you like~
\(\color{#0cbb34}{\text{End of Quote}}\)
Ya can you?
pls and thx<3

Answer 18

m∠SQR = 108°

Answer 19

just 106°

Answer 20

\(\color{#0cbb34}{\text{Originally Posted by}}\) @stranger2
\(\color{#0cbb34}{\text{Originally Posted by}}\) @nevaehhh
\(\color{#0cbb34}{\text{Originally Posted by}}\) @stranger2
\(\color{#0cbb34}{\text{Originally Posted by}}\) @nevaehhh
Ok, to start off, which one do you think it is ?
\(\color{#0cbb34}{\text{End of Quote}}\)
I thought it was B
\(\color{#0cbb34}{\text{End of Quote}}\)
I don't believe it's B, but I can walk you through it if you like~
\(\color{#0cbb34}{\text{End of Quote}}\)
Ya can you?
pls and thx<3
\(\color{#0cbb34}{\text{End of Quote}}\)
Ok well- when we deal with angles, we have a couple of rules aka theorems... right ? Has your teacher talked about any theorems ?

Answer 21

yes
but I dont rly understand them
so..

Answer 22

Ok- that's fine I can explain the ones you need to solve this~

Answer 23

Alright in the choices, let's try to eliminate some...

Answer 24

I think we can eliminate B, doesn't that angle look a littleee too wide to be 53 degrees ? This isn't mathematic, but we can use observation~

Answer 25

\(\color{#0cbb34}{\text{Originally Posted by}}\) @nevaehhh
I think we can eliminate B, doesn't that angle look a littleee too wide to be 53 degrees ? This isn't mathematic, but we can use observation~
\(\color{#0cbb34}{\text{End of Quote}}\)
74*

Answer 26

\(\color{#0cbb34}{\text{Originally Posted by}}\) @nevaehhh
\(\color{#0cbb34}{\text{Originally Posted by}}\) @nevaehhh
I think we can eliminate B, doesn't that angle look a littleee too wide to be 53 degrees ? This isn't mathematic, but we can use observation~
\(\color{#0cbb34}{\text{End of Quote}}\)
74*
\(\color{#0cbb34}{\text{End of Quote}}\)
oh true, it is too wide
so yes we can eliminate that

Answer 27

\(\color{#0cbb34}{\text{Originally Posted by}}\) @xxxFrancisco14xx
m∠QST = 72°
\(\color{#0cbb34}{\text{End of Quote}}\)
Might I ask how u got this answer?

Answer 28

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Hoodmemes
\(\color{#0cbb34}{\text{Originally Posted by}}\) @xxxFrancisco14xx
m∠QST = 72°
\(\color{#0cbb34}{\text{End of Quote}}\)
Might I ask how u got this answer?
\(\color{#0cbb34}{\text{End of Quote}}\)
please wait until we're done, not trynna be rude~

Answer 29

what you know about parallelograms ? how are the opposite angles and sides ?

Answer 30

Ok... so now we have A, C and D...

Answer 31

Which one do you think it is ?

Answer 32

...maybe A
irdk

Answer 33

I don't believe that's right but it's all good- now let's get into these theorems~

Answer 34

Alright... now look at this parallelogram. It looks like it's kinda "chopped in half" right ? Like someone put two exact triangles together, to make this shape... now since these triangles are "exact", what does this mean about their angles ?

Answer 35

equal
or congurent
right

Answer 36

Yep ! Since, the triangles are the same... their angles are congruent~

Answer 37

oh ya

Answer 38

Alright... so we already know that <STR=106... now look at it again, does that angle sit in a triangle ?

Answer 39

Is it "in" a triangle ?

Answer 40

no?

Answer 41

oh yes

Answer 42

I think-

Answer 43

That represents the angle- the angle is "in" that triangle... ok now remember what we said about the triangles being congruent ?

Answer 44

yes the triangles are congruent ...

Answer 45

Ok... now what is the name of that angle ? Look back at the problem rq~

Answer 46

We will discuss the theorem after you get it

Answer 47

so im supposed to be finding the name of that top angle right

Answer 48

\(\color{#0cbb34}{\text{Originally Posted by}}\) @stranger2
so im supposed to be finding the name of that top angle right
\(\color{#0cbb34}{\text{End of Quote}}\)
Yes ma'am

Answer 49

SQR
or
RQS
I think

Answer 50

Good job ! RQS=106~

Answer 51

thx
so wut else ..

Answer 52

Now... time for theorems aka proofs

Answer 53

yes...

Answer 54

All you really need to know is that when two angles are across from each other aka alternate, then they are congruent- lemme draw an example rq~

Answer 55

ohhh
and ok
I'll wait

Answer 56

yes

Answer 57

so there opposite exterior angles bcccccccc there on the opposite side and on the outside right?

Answer 58

so,

Answer 59

when the angles are opposite, they are equal

Answer 60

I see

Answer 61

1=8 and 2=7, shows Alternate EXTERIOR theorem, and 3=6 and 4=5 is the Alternate INTERIOR theorem.

Answer 62

oh ya, I get that.

Answer 63

do you need any more help with anything ? did i help ?

Answer 64

Yes you really helped a lot thank you so much <3
so wait was that it

Answer 65

yeppp- that's all

Answer 66

and you're welcome<3<3

Answer 67

I might post another one. if u hav time can u help.

Answer 68

absolutely ~