Question

simplify the result.

Answer 1

So basically
\(\LARGE\frac{b3−5b^2−4b+20}{b3−9b^2+24b−20}=\frac{(b+2)(b−2)(b−5)}{(b−2)(b−2)(b−5)
}=\frac{?}{?}\)

Answer 2

@supie I think it would be helpful if you explain how you factored the numerator =)

Answer 3

\(\color{#0cbb34}{\text{Originally Posted by}}\) @supie
So basically
\(\LARGE\frac{b3−5b^2−4b+20}{b3−9b^2+24b−20}=\frac{(b+2)(b−2)(b−5)}{(b−2)(b−2)(b−5)
}=\frac{?}{?}\)
\(\color{#0cbb34}{\text{End of Quote}}\)
\[B+2 / B-2\] ?

Answer 4

GOT IT thank you :)

Answer 5

Oh sorry

and you're welcome