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Chemistry 11 Online
gebrown1:

What is the mass (in grams) of 17.00 L of propane vapor (C₃H₈) at STP? R = 0.08314 L・bar/mol・K.

Vocaloid:

at STP, 1 mol of gas = 22.4L so you can divide 17.00L by 22.4L to get to moles, then multiply by the molar mass of propane vapor to get grams

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