Question

Makayla is taking a math course and is working with the perimeter of rectangles. She knows the perimeter and length of her rectangle but wants to solve for the width. Rearrange the following equation for W, where P is the perimeter, L is the length, and W is the width of the rectangle.

P = 2L + 2W

W = 2P − 2L
W equals P over 2 minus 2 times L
W equals the quantity P minus 2 times L all over 2
W = 2P + 2L

Answer 1

its part of the equation

Answer 2

could you help me solve the equation

Answer 3

Yes, to make the equation easier plug in random numbers to see what you get and then plug in numbers into the answers choices *same number, same spot* it will take longer but you will get the answer

Answer 4

i will try that
thanks

Answer 5

@Convert I know the answer, I just dont know how to put it into words, like walk them through

Answer 6

Ok so P = 2L + 2W is the formula for perimeter
So using this we have to solve for W so we use a simple algebraic expression:

P = 2L + 2W
-2W -2W

-2W + P = 2L
-P -P

-2W = -P + 2L
-2W/-2 = (-P/2) + (2L/-2)
W = -P - 2L all dived by 2
Answer: 3rd option

Answer 7

Sorry I had to make the spacing different so the equal sign would allign

Answer 8

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Convert
Ok so P = 2L + 2W is the formula for perimeter
So using this we have to solve for W so we use a simple algebraic expression:

P = 2L + 2W
-2W -2W

-2W + P = 2L
-P -P

-2W = -P + 2L
-2W/-2 = (-P/2) + (2L/-2)
W = -P - 2L all dived by 2
Answer: 3rd option
\(\color{#0cbb34}{\text{End of Quote}}\)
I knew it was C, thanks I just didn't know how to put it into words

Answer 9

\(\color{#0cbb34}{\text{Originally Posted by}}\) @simsharrison
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Convert
Ok so P = 2L + 2W is the formula for perimeter
So using this we have to solve for W so we use a simple algebraic expression:

P = 2L + 2W
-2W -2W

-2W + P = 2L
-P -P

-2W = -P + 2L
-2W/-2 = (-P/2) + (2L/-2)
W = -P - 2L all dived by 2
Answer: 3rd option
\(\color{#0cbb34}{\text{End of Quote}}\)
I knew it was C, thanks I just didn't know how to put it into words
\(\color{#0cbb34}{\text{End of Quote}}\)
Oh lol well there you go 😂

Answer 10

And I meant divided* not dived

Answer 11

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Convert
\(\color{#0cbb34}{\text{Originally Posted by}}\) @simsharrison
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Convert
Ok so P = 2L + 2W is the formula for perimeter
So using this we have to solve for W so we use a simple algebraic expression:

P = 2L + 2W
-2W -2W

-2W + P = 2L
-P -P

-2W = -P + 2L
-2W/-2 = (-P/2) + (2L/-2)
W = -P - 2L all dived by 2
Answer: 3rd option
\(\color{#0cbb34}{\text{End of Quote}}\)
I knew it was C, thanks I just didn't know how to put it into words
\(\color{#0cbb34}{\text{End of Quote}}\)
Oh lol well there you go 😂
\(\color{#0cbb34}{\text{End of Quote}}\)
ATTENTION please -P/(-2) not equal -P you missed from (-P/2) one minus sign of 2
please correct it ...

Answer 12

and

-2W = -P + 2L
-2W/-2 = (-P/2) + (2L/-2)
W = -P - 2L all dived by 2 here not divided by 2 bc. you divide them by -2, minus 2

@Convert Attention please !

Answer 13

Please I need some help, here's the worded problem:
Find the dimensions of the largest rectangle that can inscribed in the right triangle with sides 3, 4 and 5 (a) two sides of the rectangle are on the legs of the triangle, and if (b) a side of the rectangle is on the hypotenuse of the triangle.
Thankyou in advance!!

Answer 14

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9
and

-2W = -P + 2L
-2W/-2 = (-P/2) + (2L/-2)
W = -P - 2L all dived by 2 here not divided by 2 bc. you divide them by -2, minus 2

@Convert Attention please !
\(\color{#0cbb34}{\text{End of Quote}}\)
Oh thank you @jhonyy9 for pointing that out!
I completely missed it at first my bad-