Question

A compound was analyzed and was found to contain the following percentages of the elements by mass: barium, 89.56%; oxygen, 10.44%. Determine the empirical formula of the compound.

Answer 1

You can find the answer and watch how they solve it here: https://www.numerade.com/questions/a-compound-was-analyzed-and-was-found-to-contain-the-following-percentages-of-the-elements-by-mass-b/

Answer 2

) Assume 100 g of the compound is present. Therefore:

barium = 89.56 g

oxygen = 10.44 g

2) Convert to moles:

barium = 89.56 g / 137.33 g/mol = 0.65215 mol

oxygen = 10.44 g / 16.00 g/mol = 0.6525 mol

3) Divide by smallest (looking for smallest whole-number ratio):

barium = 0.65215 mol / 0.65215 mol = 1

oxygen = 0.6525 mol / 0.65215 mol = 1

Answer 3

so its BaO?

Answer 4

correct :)

Answer 5

thank you :)

Answer 6

no problem

Answer 7

\(\color{#0cbb34}{\text{Originally Posted by}}\) @ZombieLover
) Assume 100 g of the compound is present. Therefore:

barium = 89.56 g

oxygen = 10.44 g

2) Convert to moles:

barium = 89.56 g / 137.33 g/mol = 0.65215 mol

oxygen = 10.44 g / 16.00 g/mol = 0.6525 mol

3) Divide by smallest (looking for smallest whole-number ratio):

barium = 0.65215 mol / 0.65215 mol = 1

oxygen = 0.6525 mol / 0.65215 mol = 1
\(\color{#0cbb34}{\text{End of Quote}}\)
Its better if u don't copy word for word from another user on a different sites answer.