What is the conjugate of the following complex number: 6 - 2i

Question

Zelynross · Answer

@Ultrilliam

KjSaif · Answer

Ok the first step is that you rewrite (6 - 2i)  into
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> $$2\times 3 - 2i$$

KjSaif · Answer

next you factor out the common term (2 for this question) 
$$2(3-i)$$

KjSaif · Answer

If you rewrite this in standard complex form you would get the same answer as orignal,  are there any answer choices?

Zelynross · Answer

no

KjSaif · Answer

ok since you can't factor $$6 - 2i$$ any further, you instead flip the subtraction with the opposite term, addition.

KjSaif · Answer

This gives you an answer of $$6+2i$$

KjSaif · Answer

All you do is negate the term with "i"

KjSaif · Answer

hope this helps.

Zelynross · Answer

preciate it

KjSaif · Answer

np

Zelynross · Answer

Find the quotient (using complex conjugates)
1 over 6-2i

jhonyy9 · Answer

have you understood it what mean conjugate ?

$$\frac{ 1 }{ 6 -2i } = $$

- so when there is a term with ,,i" in denominator we need eliminate it - so in this way we need multiplie top and bottom by conjugate of denominator

how you think what maybe the conjugate of 6 -2i ? 
use these above wrote

@Laylalyssa any idea here pls. ? do you know the way ?

jhonyy9 · Answer

@supie any idea here pls ?

Laylalyssa · Answer

nah me no know the way

jhonyy9 · Answer

have you learn about complex numbers ?

Laylalyssa · Answer

uhh no..