Question

. A random variable r is normally distributed with a mean of 7 and a standard deviation of 1.5. Find the
value of w so that P ( 8.8 < r < w) = .0800

Answer 1

@XioGonz any idea here ? pls.

Answer 2

( 8.8< r<w ) = 0.08

( r < w) -( r < 8.8) = 0.08

( r<w) = 0.08 + (r < 8.8)

(r<w) = 0.08 + ( z < (8.8-7)/1.5)

= 0.08 + ( z < 1.2)

= 0.08 + 0.88493

= 0.96493

(z < 1.811006) = 0.96493

But wait there's more..

Answer 3

z = (w-m)

1.811006 = (w- 7)/1.5

w = 1.811006*1.5+7

So


= 9.716509

Answer 4

\(\color{#0cbb34}{\text{Originally Posted by}}\) @XioGonz
( 8.8< r<w ) = 0.08

( r < w) -( r < 8.8) = 0.08
ok ty - but can you explain how you get this result of ... ? -(r<8,8) i m not sure that the student who asked the problem will can understanding it ...
( r<w) = 0.08 + (r < 8.8)

(r<w) = 0.08 + ( z < (8.8-7)/1.5)

= 0.08 + ( z < 1.2)

= 0.08 + 0.88493

= 0.96493

(z < 1.811006) = 0.96493

But wait there's more..
\(\color{#0cbb34}{\text{End of Quote}}\)

Answer 5

Find the
value of w so that P ( 8.8 < r < w) = .0800

-from the question.