Question

Factor the expression, picture provided!

Answer 1

(((x^3) + (2•3x^2)) + 4x) + 24

We see that x^3+6x^2+4x+24 Isn't a perfect cube so we got to factor into 2 groups

Group 1: 4x+24
Group 2: 6x^2+x^3

Pull out from each group separately

Group 1: (x+6) • (4)
Group 2: (x+6) • (x^2)

Add up both of the groups

(x+6) • (x^2+4)

Find the roots of: F(x) = x^2+4

HENCE

(x^2 + 4) • (x + 6)

Answer 2

Ty again!!

Answer 3

Np!

Answer 4

\(\color{#0cbb34}{\text{Originally Posted by}}\) @XioGonz
Np!
\(\color{#0cbb34}{\text{End of Quote}}\)
Stop being so smart I’m mad how smart you are

Answer 5

\(\color{#0cbb34}{\text{Originally Posted by}}\) @CripQUEZZ
\(\color{#0cbb34}{\text{Originally Posted by}}\) @XioGonz
Np!
\(\color{#0cbb34}{\text{End of Quote}}\)
Stop being so smart I’m mad how smart you are
\(\color{#0cbb34}{\text{End of Quote}}\)
Uh. SOhRry